Answer:
The conversion of ADP to ATP using light energy is the best description of photophosphorylation.
I would think that the answer would be C! Good Luck, tell me if it's correct please! :D
Answer:
B) 1/2 X 1/2 = 1/4
Explanation:
It happens when both the parents are heterozygous for the trait. The cross related to this result is shown as under:
Father Mother
Bb x Bb
/ \ / \
Gametes: B b B b
| | | |
Probability: 1/2 1/2 1/2 1/2
The probability of formation of 'b' gamete from father is 1/2 because there are only two gametes 'B' and 'b' and out of these two one will be assorted as 'B' and another one as 'b' and from mother also the probability of formation of 'b' gamete is 1/2.
Now the assortment of gametes with each other is an independent event i.e. any gamete from father can fuse with any gamete of mother so the overall probability of formation of 'bb' genotype will be 1/2 x 1/2 = 1/4.
<span>The main significance of the fossils Darwin found
was that they inspired/reenforced his theory of evolution by showing
that the bone structures of species have changed over time. </span>
Answer:
A. the heterozygote advantage
Explanation:
Heterozygote advantage is the condition where the heterozygous individual has higher relative fitness than both homozygous dominant and homozygous recessive individual. This means that the heterozygote individual has higher chances of surviving than both the homozygous counterparts. Sickle cell anemia is a recessive inherited disorder in which oxygen carrying hemoglobin has an abnormal structure. Hence, the resultant RBCs are not spherical but have crescent sickle shape. The oxygen carrying capacity of such RBCs is drastically reduced but they are unaffected by malarial parasite due to their abnormal structure.
- A person with both the recessive genes for sickle cell would not be able to survive due to insufficient oxygen transport in body.
- A person with both the dominant genes would be free of sickle cell anemia but in case of malaria would not be able to survive as the normal RBCs would be hijacked by the parasite.
- A hetrerozygote would survive both in malaria and sickle cell condition since he has enough normal RBCs for oxygen transport but also has sickle cell RBCs which are unaffected by malarial parasite.
