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drek231 [11]
3 years ago
5

Factor completely 7x3y +14x2y3 − 7x2y2.

Mathematics
2 answers:
netineya [11]3 years ago
8 0
The answer to the question is b

olganol [36]3 years ago
8 0

Answer:

\largeboxed{7x^2y(x+2xy^2-y)}

Step-by-step explanation:

7x^3y+14x^2y^3-7x^2y^2\\\\7x^3y=\boxed7\cdot\boxed{x}\cdot\boxed{x}\cdot{x}\cdot \boxed{y}\\\\14x^2y^3=2\cdot\boxed7\cdot\boxed{x}\cdot\boxed{x}\cdot x\cdot\boxed{y}\cdot y\cdot y\\\\7x^2y^2=\boxed7\cdot\boxed{x}\cdot\boxed{x}\cdot\boxed{y}\cdot y\\\\7x^3y+14x^2y^3-7x^2y^2=\boxed7\cdot\boxed{x}\cdot\boxed{x}\cdot\boxed{y}(x+2\cdot x\cdot y\cdot y-y)\\\\=7x^2y(x+2xy^2-y)

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Firdavs [7]

Answer: So what is two plus two plus two?

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Step-by-step explanation: Hope I helped you out <3

-Carrie

5 0
3 years ago
Someone pls help asap this is due tmrw !!<br><br> x - 3y = -12<br> 2x + 3y = 3
hram777 [196]

Answer:

Step-by-step explanation:

to solve this system of equations we will add them

x-3y=-12

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4 0
3 years ago
-\frac{4\left(x+3\right)}{5}=4x-12
Keith_Richards [23]

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Step-by-step explanation:

6 0
3 years ago
Vending machines can be adjusted to reject coins above and below certain weights. The weights of legal U.S. quarters have a norm
tigry1 [53]

Answer: The percentage of legal quarters will be rejected by the vending machine = 2.275%

Step-by-step explanation:

Given: The weights of legal U.S. quarters have a normal distribution with a mean of 5.67 grams and a standard deviation of 0.07 gram.

Let x be the weights of legal U.S. quarters .

Required probability: P(x5.81)

=P(\dfrac{x-\mu}{\sigma}\dfrac{5.81-5.67}{0.07})\\\\=P(z2)\approx0.02275    \ \ \ [By\  P-value\ calculator]

The percentage of legal quarters will be rejected by the vending machine = 2.275%

5 0
2 years ago
In ΔFGH, the measure of ∠H=90°, the measure of ∠F=60°, and HF = 60 feet. Find the length of GH to the nearest foot.
AlladinOne [14]

Answer:

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Step-by-step explanation:

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tan(60) = X/60

X = 60×tan(60)

X = 103.9230484541

X = 104 (3 sf)

6 0
3 years ago
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