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zhenek [66]
3 years ago
15

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confide

nce intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 50 home theater systems has a mean price of ​$113.00. Assume the population standard deviation is ​$15.20.
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

90% confidence interval, (109.47,116.53)

For 95% confidence interval (108.79,117.21)

Step-by-step explanation:

n =50

mean = 113

standard deviation = 15.20

a.) For 90% confidence interval, z=1.645

90% confidence interval is

(113 - \frac{1.645*15.20}{sqrt(50)},113 + \frac{1.645*15.20}{sqrt(50)}}

=(113 - 3.53, 113 + 3.53)

=(109.47,116.53)

b.)For 95% confidence interval, z = 1.96

95% confidence interval is

(113 - \frac{1.96*15.20}{\sqrt(50)},113 + \frac{1.96*15.20}{\sqrt(50)}

=(113 - 4.21, 113 + 4.21)

=(108.79,117.21)

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Step-by-step explanation:

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The rate StartFraction 165 ounces Over 11 boxes EndFraction describes the relationship between the number of boxes and the weigh
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Answer:

15 ounces per box

Step-by-step explanation:

The rate StartFraction 165 ounces Over 11 boxes EndFraction describes the relationship between the number of boxes and the weight of the crackers in the boxes. What is the weight, in ounces, of one box?

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Answer:

5 rad

Step-by-step explanation:

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Therefore in this case, you know the arc length (81.5 cm), and the radius (16.3 cm), and can solve for the angle \theta using the above equation as shown below:

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3 years ago
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