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Vitek1552 [10]
3 years ago
15

Answer asap i will make you brainliest!!!

Mathematics
1 answer:
Ahat [919]3 years ago
6 0

ers as the elements in the rows near the bottom.

C.  

have higher atomic numbers than the elements in the rows near the bottom.

D.  

have lower atomic numbers than the elements in the rows near the bottom.

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What is the area of this trapezoid?
Ivanshal [37]

Answer: 357 cm²

Step-by-step explanation: In this problem, were asked to find the area of the trapezoid shown. Remember that a trapezoid is a quadrilateral with one pair of parallel sides. The formula for the area of a trapezoid is shown below

The b's are the bases or the parallel sides and the h represents the height.

So in the trapezoid shown, the bases are 15 cm and 27 cm and the height is 17 cm.

Plugging this information into the formula, we have .

Next, the order of operations tells us that we must simplify inside the parentheses first. 15 cm + 27 cm is 42 cm and we have

1/2 × 42 cm is 21 cm and we have (21 cm)(17 cm) which is 357 cm².

So the area of the trapezoid shown is 357 cm².

5 0
3 years ago
F(-5) if(x) - 4x + 2
sashaice [31]

Answer:

22

Step-by-step explanation:

-4(-5)+2

20+2

22

3 0
3 years ago
Find the domain and range of f(x) = 2 square root of x-2
Neporo4naja [7]
f(x)=2\sqrt{x-2}\\\\The\ domain:\\x-2\geq0\to x\geq2\\\boxed{x\in[2;\ \infty)}\\\\The\ range:\\\boxed{y\in[0;\ \infty)}

If\ f(x)=2\sqrt{x}-2,\ then\\\\The\ domain:\boxed{x\in[0;\ \infty)}\\\\The\ range:\boxed{y\in[-2;\ \infty)}
5 0
3 years ago
•** Plss help me **•
VashaNatasha [74]

Answer:

30

Step-by-step explanation:

You can use the triangle area theorem-

15x4(/2)=30

4 0
2 years ago
An archery target consists of a circular bull's-eye with radius x, surrounded by four rings with width y. What is the area of th
amid [387]
<span>given:
   bull's eye radius= x
 width of surrounding rings=y

   solution:
   Radius of the circle=x+4y
Area of the outermost ring=Area of the circle-Area of the penultimate ring =Ď€(x+4y)^2-Ď€(x+3y)^2
=Ď€(x^2+8xy+16y^2-x^2-9y^2-6xy)
 =Ď€(2xy+7y^2)
 hence the area of the outermost ring in terms of x and y is Ď€(2xy+7y^2).</span>
4 0
3 years ago
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