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1 year ago

Answer the questions about the following polynomial.

Mathematics

1 answer:

Vlad1618 [11]1 year ago

5 0

Answer:

1) Linear

2) Two (2 Terms means it is a Binomial)

3) 1/7

4) -x

5) -1 (-x = -1x)

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-5x+2y=6<br> -x+2y=-2 <br> what is the solution to the system of equations?

dybincka [34]

Step-by-step explanation:

$- 5x + 2y = 6 \\ - x + 2y = - 2 \\ \\ - 5x + 2y - ( - x + 2y) = 6 - ( - 2) \\ - 5x + 2y + x - 2y = 6 + 2 \\ - 4x = 8 \\ \frac{ - 4x}{ - 4} = \frac{8}{ - 4 } \\ x = (- 2) \\ \\ -5x + 2y = 6 \\ - 5 \times - 2 + 2y = 6 \\ 10 + 2y = 6 \\ 2y = 6 - 10 \\ 2y = - 4 \\ \frac{2y}{2} = \frac{ - 4}{2} \\ y = - 2 \\ now \: lets \: see \: whether \\ this \: equation \: is \: correct. \\ - x + 2y = - 2 \\ - ( - 2) + 2 \times - 2 = - 2 \\ 2 + 2 \times - 2 = - 2 \\ 2 - 4 = - 2 \\ - 2 = - 2 \\ yes \: this \: equation \: is \\ correct.$

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2 years ago

Three cards are chosen from a standard deck of 52 playing cards with replacement what is the orobsbility every card will be a he

Ne4ueva [31]

1/4 x 1/4 x 1/4 = 1/64

There is a 1/64 chance that they will all be hearts.

7 0

3 years ago

What is the product of −3/11 and <br> −2/15?

Dafna11 [192]

Multiply -3/11 and -2/15 straight across

-3(-2) = 6
11(15) = 165

6/165 is your product, or 0.036 (rounded)

hope this helps

5 0

3 years ago

Read 2 more answers

What are the three types of triangles, based on ANGLES?<br> Draw an example for each one.

artcher [175]

Answer:

Right Triangle, Acute Triangle, and Obtuse Triangle

Step-by-step explanation:

I can't draw it here but the right triangle has a side of 90°.

An acute triangle has a side smaller than 90°.

An obtuse triangle has a side bigger than 90°.

5 0

2 years ago

Ask your teacher find the limit. use l'hospital's rule where appropriate. if there is a more elementary method, consider using i

liberstina [14]

Answer:

ln(5/3)

Step-by-step explanation:

The desired limit represents the logarithm of an indeterminate form, so L'Hopital's rule could be applied. However, the logarithm can be simplified to a form that is not indeterminate.

<h3>Limit</h3>

We can cancel factors of (x-1), which are what make the expression indeterminate at x=1. Then the limit can be evaluated directly by substituting x=1.

$\diplaystyle \lim\limits_{x\to1}{(\ln(x^5-1)-\ln(x^3-1))}=\lim\limits_{x\to1}\ln{\left(\dfrac{x^5-1}{x^3-1}\right)}\\\\=\lim\limits_{x\to1}\ln\left(\dfrac{x^4+x^3+x^2+x+1}{x^2+x+1}\right)=\ln{\dfrac{5}{3}}$

8 0

1 year ago