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3 years ago

© ABCD is a rectangle with sides 6 cm and

Mathematics

1 answer:

Nikolay [14]3 years ago

4 0

Answer:

Step-by-step explanation:

If the sides of the rectangle is 6cm and 8cm, then we mean that, the length and breadth are 6cm and 8cm

The diagonal which cross at AX will be the hypotenus of the triangle formed by drawing the diagonal.

Hence,

Hypotenus = sqrt (opposite² + adjacent²)

AX = sqrt[(8²) + (6²)]

AX = sqrt(64 + 36)

AX = sqrt(100)

AX = 10

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Hi I need this asap if you also explain the work on how you got answers plz and thank you

weeeeeb [17]

Answer:

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$\frac{9}{5} —>1 \frac{4}{5}$

*explain ; We put the 5 in the denominator and 5 multiply 1 + 4 so equal 9 so the choice 9/5 .

Ans; 7/3—> 2 1/3

*explain ; We put the 3 in the denominator and 3 multiply 2 + 1 so equal 7 so the choice 7/3 .

Ans; 12/10 —> 1 1/5

*explain; simple (12 and 10) ÷ 2 so equal 6/5

We put the 5 in the denominator and 5 multiply 1 + 1 so equal 6 so the choice 6/5 =12/10 .

$\frac{12 \div 2}{10 \div 2} = \frac{6}{5} = 1 \frac{1}{5}$

Q/ Compare the fractions;Ans;

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$2 \frac{1}{6} > \frac{5}{9}$

* explain; 2 1/6 —> We put the 6 in the denominator and 6 multiply 2 + 1 so equal 13 so equal 13/6

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Q/ Multiply;Ans;

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$\frac{2}{3} \times \frac{3}{8} = \frac{6}{24} = \frac{1}{4}$

Q/Divide;Ans;

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$\frac{8}{9} \div \frac{1}{3} \\ \\ \frac{8}{9} \times \frac{3}{1} = \frac{24}{9} = \frac{8}{3}$

I hope I helped you^_^

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