M(1,-7): Plot the points and then find your slope which is -8/8 or -1. Separate each point into 5 pieces of the left part of the segment and 3 on the right.
-5 is colder than -3 is correct.
hope this helps!
1. The counterclockwise rotation by 90° about the origin has rule:
(x,y)→(-y,x).
Then
(-3,-1)→(1,-3).
2. Translation 4 units up has rule:
(x,y)→(x,y+4).
Then
(1,-3)→(1,1).
Answer: after composition of transformations the image point has coordinates (1,1).
It all depends on what you are comparing it to... if you want what fraction of a meter it is...
There are 10 decimeters per 1 meter so 1 dm is 1/10 of a meter which means 6 dm = 6 × 1/10 = 6/10 = 3/5
6 dm = 3/5 m
Answer with Step-by-step explanation:
1.In triangle ABC
AB=BC
Let AB=BC=x and AC=y
Perimeter of triangle ABC=25
![x+x+y=25](https://tex.z-dn.net/?f=x%2Bx%2By%3D25)
...(1)
...(2)
Adding equation (1) and (2)
![3x=29](https://tex.z-dn.net/?f=3x%3D29)
![x=\frac{29}{3}=9.67](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B29%7D%7B3%7D%3D9.67)
Substitute x=9.67 in equation (2)
![9.67-y=4](https://tex.z-dn.net/?f=9.67-y%3D4)
![y=9.67-4=5.67](https://tex.z-dn.net/?f=y%3D9.67-4%3D5.67)
![AB=BC=9.67](https://tex.z-dn.net/?f=AB%3DBC%3D9.67)
![AC=5.67](https://tex.z-dn.net/?f=AC%3D5.67)
2.![m\angle R=2x+11](https://tex.z-dn.net/?f=m%5Cangle%20R%3D2x%2B11)
![m\angle S=3x+23](https://tex.z-dn.net/?f=m%5Cangle%20S%3D3x%2B23)
![m\angle T=x+42](https://tex.z-dn.net/?f=m%5Cangle%20T%3Dx%2B42)
![m\angle R+m\angle S+m\angle T=180^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20R%2Bm%5Cangle%20S%2Bm%5Cangle%20T%3D180%5E%7B%5Ccirc%7D)
By using triangle angle sum property
Substitute the values then we get
![3x+42+4x-11+x+13=180](https://tex.z-dn.net/?f=3x%2B42%2B4x-11%2Bx%2B13%3D180)
![8x+44=180](https://tex.z-dn.net/?f=8x%2B44%3D180)
![8x=180-44=136](https://tex.z-dn.net/?f=8x%3D180-44%3D136)
![x=\frac{136}{8}=17](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B136%7D%7B8%7D%3D17)
Substitute the value
![m\angle R=3(17)+42=93^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20R%3D3%2817%29%2B42%3D93%5E%7B%5Ccirc%7D)
![m\angle S=4(17)-11=57^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20S%3D4%2817%29-11%3D57%5E%7B%5Ccirc%7D)
![m\angle T=17+13=30^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20T%3D17%2B13%3D30%5E%7B%5Ccirc%7D)
![m\angle R>m\angle S](https://tex.z-dn.net/?f=m%5Cangle%20R%3Em%5Cangle%20S)
![m\angle S>m\angle T](https://tex.z-dn.net/?f=m%5Cangle%20S%3Em%5Cangle%20T)
(Side ST is opposite to angle R, Side RT is opposite to angle S
(side RS is opposite to angle T)
When a>b
Then , opposite side of a> opposite side of b
RS<RT<ST
3.![m\angle R=2x+11](https://tex.z-dn.net/?f=m%5Cangle%20R%3D2x%2B11)
![m\angle S=3x+23](https://tex.z-dn.net/?f=m%5Cangle%20S%3D3x%2B23)
![\angle T=x+42](https://tex.z-dn.net/?f=%5Cangle%20T%3Dx%2B42)
![m\angle R+m\angle S+m\angle T=180^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20R%2Bm%5Cangle%20S%2Bm%5Cangle%20T%3D180%5E%7B%5Ccirc%7D)
By using triangle angle sum property
Substitute the values then we get
![2x+11+3x+23+x+42=180](https://tex.z-dn.net/?f=2x%2B11%2B3x%2B23%2Bx%2B42%3D180)
![6x+76=180](https://tex.z-dn.net/?f=6x%2B76%3D180)
![6x=180-76](https://tex.z-dn.net/?f=6x%3D180-76)
![6x=104](https://tex.z-dn.net/?f=6x%3D104)
![x=\frac{104}{6}=17.3](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B104%7D%7B6%7D%3D17.3)
Substitute the value
![m\angle R=2(17.3)+11=45.6](https://tex.z-dn.net/?f=m%5Cangle%20R%3D2%2817.3%29%2B11%3D45.6)
![m\angle S=3(17.3)+23=74.9](https://tex.z-dn.net/?f=m%5Cangle%20S%3D3%2817.3%29%2B23%3D74.9)
![m\angle T=17.3=42=59.3](https://tex.z-dn.net/?f=m%5Cangle%20T%3D17.3%3D42%3D59.3)
![m\angle S>m\angle T](https://tex.z-dn.net/?f=m%5Cangle%20S%3Em%5Cangle%20T)
![m\angle T>m\angle R](https://tex.z-dn.net/?f=m%5Cangle%20T%3Em%5Cangle%20R)
RT>RS
RS>ST
ST<RS<RT