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3 years ago

Whats the answer to this numeric algebraic expression

Mathematics

1 answer:

Degger [83]3 years ago

4 0

Answer:

a+b+2

Step-by-step explanation:

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Graph f(x)= -(x-2)²+4<img src="https://tex.z-dn.net/?f=" id="TexFormula1" title="" alt="" align="absmiddle" class="latex-formula

Mandarinka [93]

Answer: See the graph attached.

Step-by-step explanation:

The standard form of a quadratic function is:

$f(x)=a(x-h)+k$

Where (h,k) is the vertex of the parabola.

If $a$ is negative, then the parabola opens down.

Then, for the function:

$f(x)=-(x-2)^2+4$

You can identify:

$h=2\\k=4$

Then the vertex of the parabola is at (2,4)

Note that $a=-1$ , therefore the parabola opens down.

Find the intersection with the x-axis. Substitute $f(x)=0$ and solve for x:

$0=-(x-2)^2+4\\0=x^2-4x\\0=x(x-4)\\\\x_1=0\\x_2=4$

Knowing that the vertex is at (2,4), the parabola opens down and it intersects the x-axis at x=0 and x=4, you can graph the function, as you observe in the figure attached.

7 0

4 years ago

Area of a circle with a diameter of

ivann1987 [24]

The diameter is the radius ×2

5 0

4 years ago

Please help! the questions are in the photo.

Paha777 [63]

$\bold{ANSWER:}$
53%

$\bold{SOLUTION:}$

6 0

2 years ago

PLSS HELPPP MEE!!! It’s timed

Ne4ueva [31]

1.) 2.5

2.) 3

3.)12.5

Pls give brainliest

3 0

4 years ago

Suppose that the distance, in miles, that people are willing to commute to work is an exponential random variable with a decay p

garik1379 [7]

Answer:

m = $\frac{1}{20}$
μ = 20
σ = 20

The probability that a person is willing to commute more than 25 miles is 0.2865.

Step-by-step explanation:

Exponential probability distribution is used to define the probability distribution of the amount of time until some specific event takes place.

A random variable X follows an exponential distribution with parameter m.

The decay parameter is, m.

The probability distribution function of an Exponential distribution is:

$f(x)=me^{-mx}\ ;\ m>0, x>0$

Given: The decay parameter is, $\frac{1}{20}$

X is defined as the distance people are willing to commute in miles.

The decay parameter is m = $\frac{1}{20}$ .
The mean of the distribution is: $\mu=\frac{1}{m}=\frac{1}{\frac{1}{20}}=20$ .
The standard deviation is: $\sigma=\sqrt{variance}= \sqrt{\frac{1}{(m)^{2}} } =\frac{1}{m} =\frac{1}{\frac{1}{20}} =20$

Compute the probability that a person is willing to commute more than 25 miles as follows:

$P(X>25)=\int\limits^{\infty}_{25} {\frac{1}{20} e^{-\frac{1}{20}x}} \, dx \\=\frac{1}{20}|20e^{-\frac{1}{20}x}|^{\infty}_{25}\\=|e^{-\frac{1}{20}x}|^{\infty}_{25}\\=e^{-\frac{1}{20}\times25}\\=0.2865$

Thus, the probability that a person is willing to commute more than 25 miles is 0.2865.

7 0

4 years ago