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DochEvi [55]
3 years ago
12

Quadrilateral CDEF is reflected across the x-axis and translated 3 units left to create quadrilateral GHJK .

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer- KG⎯∥JH⎯

the given figure is a trapezium in which CF||DE

Reflection of figure CDEF and shifting it by 3 units does not change the shape of the figure but changes only its position in the x-y plane.

so, the shape of the figure GHJK will be same as that of CDEF.

so sides, KG⎯∥JH⎯

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An equation in point slope form that passes through (9, -2) and (-3, 2)
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4 years ago
The lengths of two sides of a triangle are 12 ft and 13 ft. find the range of possible lengths for the third side
mihalych1998 [28]
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3 years ago
Select the correct answer from each drop-down menu. The graph represents the piecewise function.
kvasek [131]

The functions will be defined as y = x² if 0 ≤ x < 3, y = -x + 10 if 3 < x ≤ 6, and y = x + 2 if 6 ≤ x ≤ 10.

<h3>What is a function?</h3>

A statement, principle, or policy that creates the link between two variables is known as a function. Functions are found all across mathematics and are required for the creation of complex relationships.

The graph is given below.

The function can be defined as

The parabolic equation will be

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The equation of the absolute function will be

f(x) = |x - 6| + 4

Then we have

f(x) = \left\{\begin{matrix}y=x^2 & 0\leq x < 3 \\\\y=-x+10 & 3 < x\leq 6 \\\\y=x+2 & 6\leq x \leq 10 \\\end{matrix}\right.

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brainly.com/question/5245372

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2 years ago
Part C: Find the distance from B to E and from P to E. Show your work. (4 points)
My name is Ann [436]

Answer:

Part 1) BE=266\frac{2}{3}\ ft

Part 2) PE=233\frac{1}{3}\ ft

Step-by-step explanation:

Part  1)

<u><em>Find the distance from B to E</em></u>

To solve this problem I assume that CGRP is a parallelogram

so

Triangles CGB and PEB are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

so

\frac{BG}{BE}=\frac{CB}{PB}

substitute the values

\frac{400}{BE}=\frac{300}{200}

solve for BE

BE=400(200)/300

BE=\frac{800}{3}\ ft

Convert to mixed number

BE=\frac{800}{3}\ ft=\frac{798}{3}+\frac{2}{3}=266\frac{2}{3}\ ft

Part 2)

<u><em>Find the distance from P to E</em></u>

\frac{CG}{PE}=\frac{CB}{PB}

substitute the values

\frac{350}{PE}=\frac{300}{200}

solve for PE

PE=350(200)/300

PE=\frac{700}{3}\ ft

Convert to mixed number

PE=\frac{700}{3}\ ft=\frac{699}{3}+\frac{1}{3}=233\frac{1}{3}\ ft

5 0
3 years ago
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