(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]
Answer:
<h2>5</h2>
Step-by-step explanation:
Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.
On expanding the left hand side of the expression we have;
= (8x² −15x)−(x² −27x)
Open the paranthesis
= 8x² −15x−x²+27x
collect the like terms
= 8x²−x²+27x −15x
= 7x²+12x
Comparing the resulting expression with ax²+bx
7x²+12x = ax²+bx
7x² = ax²
a = 7
Also;
12x = bx
b =12
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a is equivalent to 5
Answer:
well all you need to do is try your best
Step-by-step explanation:
it would be the third one, 2/3
Since this is a 45-45-90 right triangle, the hypotenuse = sqrt2 * leg
24 is the hypotenuse so we need to find the leg.
24 = sqrt2 * leg
Divide both sides by sqrt2
leg = 16.97
A = (1/2)b*h
A = (1/2)*16.97*16.97
A = 144ft^2
Answer:
Area=36
Step-by-step explanation:
Area of rhombus: diagonal 1 x diagonal 2 divided by 2.
To find the area of a rhombus, you need to find the length of both diagonals(which is the distance between 2 points across from each other).
First, find the distance between -8 and 4 which is 12.
Next, find the distance between -1 and -7 which is 6.
12 x 6 =72
72/2=36
