14 POINTS!! PLEASE HURRY!! Solve the system by graphing. Explain you answer!!

I need help!! Will mark brainly if correctly answered.

Leto [7]

Answer:

38/50 or 19/25

Step-by-step explanation:

One way could be that you add all the marbles together to get your total marbles; 12 + 10 + 15 + 13 = 50.

Then you add all the colours expect red; 10 + 15 + 13 = 38.

Which would give me 38/50; which simplifed would be 19/25

8 0

3 years ago

Write the equation of a line in slope intercept form that has a slope of 4/5 and has a y- intercept of 0

Andreas93 [3]

Answer: y = 4\5*x

We can get this through slope intercept form.

Slope intercept form is y=mx +b where m is the slope and b is the y intercept.

We plug in 4.5 for the slope and 0 for the y-intercept.

3 0

4 years ago

I need help with this please help

agasfer [191]

Answer:

a) 3.507

b) 75.48

c) 78.41

Step-by-step explanation:

Problem A

The opposite side of the angle and the hypotenuse are involved in the question. Therefore you will be using the sine.

sin(26) = x / 8 Multiply both sides by 8

8*sin(26) = x Sin(26) = 0.4384

8*0.4384 = x Do the multiplication

3.507 = x

Problem B

The side adjacent and the hypotenuse are used in this problem. The angle is given, so you are working with the cosine.

Cos(58) = adjacent / hypotenuse

Cos(58) = 0.5299

0.5299 = 40/x Multiply both sides by x

0.5299 x = 40 Divide both sides by 0.5299

x = 40 / 0.5299

x = 75.48

Problem C

The opposite side and the adjacent side are involved and the angle is given.

Tan(71) = opposite / adjacent

tan(71) = 2.904

2.904 = x / 27 Multiply both sides by 27

2.904 * 27 = x Combine

x = 78.414

5 0

3 years ago

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Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt.

qwelly [4]

Answer:

A)

$\displaystyle \frac{dy}{dt}=-\frac{33}{8}$

B)

$\displaystyle \frac{dx}{dt}=\frac{3}{2}$

Step-by-step explanation:

x and y are differentiable functions of t, and we are given the equation:

$xy=6$

First, let's differentiate both sides of the equation with respect to t. So:

$\displaystyle \frac{d}{dt}\left[xy\right]=\frac{d}{dt}[6]$

By the Product Rule and rewriting:

$\displaystyle \frac{d}{dt}[x(t)]y+x\frac{d}{dt}[y(t)]=0$

Therefore:

$\displaystyle y\frac{dx}{dt}+x\frac{dy}{dt}=0$

A)

We want to find dy/dt when x = 4 and dx/dt = 11.

Using our original equation, find y when x = 4:

$\displaystyle (4)y=6\Rightarrow y=\frac{3}{2}$

Therefore:

$\displaystyle \frac{3}{2}\left(11\right)+(4)\frac{dy}{dt}=0$

Solve for dy/dt:

$\displaystyle \frac{dy}{dt}=-\frac{33}{8}$

B)

We want to find dx/dt when x = 1 and dy/dt = -9.

Again, using our original equation, find y when x = 1:

$(1)y=6\Rightarrow y=6$

Therefore:

$\displaystyle (6)\frac{dx}{dt}+(1)\left(-9)=0$

Solve for dx/dt:

$\displaystyle \frac{dx}{dt}=\frac{3}{2}$

5 0

3 years ago

Find the equation for the circle with center (-4,-5) and passing through (4,-2)

Sholpan [36]

Answer:

(x + 4)² + (y + 5)² = 73

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = (- 4, - 5), thus

(x - (- 4))² + (y - (- 5))² = r², that is

(x + 4)² + (y + 5)² = r²

The radius is the distance from the centre to a point on the circle.

Calculate r using the distance formula

r = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 4, - 5) and (x₂, y₂ ) = (4, - 2)

r = $\sqrt{(4+4)^2+(-2+5)^2}$

= $\sqrt{8^2+3^2}$

= $\sqrt{64+9}$ = $\sqrt{73}$ ⇒ r² = 73, thus

(x + 4)² + (y + 5)² = 73 ← equation of circle

6 0

3 years ago

Read 2 more answers