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vagabundo [1.1K]
3 years ago
14

On Mars, an object weighs 60% of its weight on Earth. Shane weighs 125 pounds on Earth.

Mathematics
1 answer:
Margarita [4]3 years ago
6 0

A and D I think or it may just be A

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Lou's car had 6.6 gallons in the 16- gallon tank on the coldest day of the year . Lou filled the tank with gas that cost 3.70 pe
Ronch [10]

Answer: $33.48

Step-by-step explanation:

Given that:

Capacity of car tank =. 16 gallons

Gallons of already filled = 6.6 gallons

Amount left of tank capacity = 16 - 6.7

Amount left of tank capacity = 9.3 gallons

Cost of gas per gallon = $3.60

Hence, amount spent in gas will be

Amount left of tank capacity * cost per gallon of gas

= 9.3 gallons * $3.60

= $33.48

Total amount spent on gas = $33.48

any more help just ask :)

8 0
3 years ago
Solve the following by elimination method <br> 11x+15y+23=0 and 7x-2y-20=0
mr Goodwill [35]
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)

Multiply equation (1) by 2:
22x + 30y + 46 = 0

Multiply equation (2) by 15:
105x - 30y - 300 = 0

Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]

Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3

Therefore, x = 2 and y = -3.
7 0
4 years ago
_______ was the most important contribution of the Shang Dynasty.
Pavlova-9 [17]
The Shang Dynasty had several contributions to history. One of the most important and notable contribution was writing. 
7 0
3 years ago
10x- 4.5 + 3x = 12x- 1.1 <br><br>x=​
AlladinOne [14]

Answer:

19..........................

7 0
3 years ago
The smaller cone is replaced with another cone of equal radii, but a height twice as big.
Bess [88]
Let's make this simple. Let's have the small cone have a radius 1 and the height 1. This would make the bigger cone have a radius of 1 and the height of 2.

With this information, lets get the volume of both cones. The formula is this:

V =  \dfrac{(\pi r^2 h)}{3}

Plug in numbers:
Small cone: V =  \dfrac{(\pi 1^2 \times 1)}{3}
Big cone: V =  \dfrac{(\pi 1^2 \times 2)}{3}

The small cone has a volume of \dfrac{\pi}{3}
The big cone has a volume of \dfrac{2 \pi}{3}

Now, you want to find how many small cones you need to have the same total volume of the big cone.

\dfrac{2\pi}{3} -  \dfrac{\pi}{3} =  \dfrac{\pi}{3} &#10;

You have the difference of pi over 3 comparing the big cone to the small one. You realize that the small cone has the same volume of that. Therefore, you need 2 small cones to have the same total volume as the larger cone
6 0
3 years ago
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