Let's say "m" is the manufactoring cost per drill (in dollars).
Then the manufactorer sells it for $4 more, so this would be:
m+4
Then the chain store sells it for 140% of the price is paid the manufactorer, so this would be "140% of (m+4)" which translates to "1.4•(m+4)" or more simply:
1.4(m+4)
P(m) = 1.4(m+4), where m is the initial manufactoring cost (in dollars).
Simplifying, you could rewrite this as:
P(m) = 1.4m + 5.6
Answer:Step-by-step explanation:
so if you buy 2 jumpers it will be the cost of 1
and 30% of 50 is 15 so 15 + 15 = 30 plus 45 =
75
Answer:
ok xd
Step-by-step explanation:
Answer:
Step-by-step explanation:
True
Answer:
A sample size of 6755 or higher would be appropriate.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error M is given by:
90% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
52% of Independents in the sample opposed the public option.
This means that 
If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?
Sample size of size n or higher when 
. So
A sample size of 6755 or higher would be appropriate.
