The floor of a storage unit is 5 feet

Determine if the following statement is true or false:

Nitella [24]

The correct answer would be that the statement is true. <span>The point-slope form of a line is y + y1 = m(x + x1), where m is the slope and (x1, y1) is a point on the line. This form of the equation of the line is helpful especially when you are asked to find the equation of the line given a point and the slope.</span>

6 0

2 years ago

The radius of the circle above is 34 mm. What is the circumference of the circle? (Use 7 = 3.14.)

Ratling [72]

213.52 mm because you have to use the formula (c=2*pi*r). First, you multiply 2 by 3.14, which is 6.28. Then, you multiply 6.28 by the radius,34, and you get 213.52 mm. Hope this helped!!!

7 0

2 years ago

A point M on a segment with endpoints X(1, −2) and Y(10, 3) partitions the segment in a 4:1 ratio. Find M. You must show all wor

kow [346]

Answer:

(8.2,2)

Step-by-step explanation:

1.

4:1 ratio means XY divided into 5 equal sections. (5 = 4+1)

4:1 ratio means (4/(4+1))

4:1 ratio means (4/5)

2.

4:1 ratio means M is 4/5 of the way from the initial point X(1, −2)

3.

get the x and y distances between (1, −2) and (10, 3)

x2-x1=9

y2-y1=5

4.

since initial point is (1, −2)

you add 1 to the new x value and

you add -2 to the new y value

ANSWERS:

x-coordinate of M = 1 + (4/5)(9) = 1 + 7.2 = 8.2

y-coordinate of M = -2 + (4/5)(5) = -2 + 4 = 2

As we move along XY from X to Y,

x increases by 9 and

y increases by 5

M is the point on XY that is 4/5 of the way from X to Y.

M is 4/5 of the distance from (1,-2) to (10,3).

To find M x and y coordinates 4/5 of distance between (x1,y1) and (x2,y2):

To find M x and y coordinates 4/5 of distance between (1,-2) and (10,3):

x-coordinate of M = 1 + (4/5)(9) = 1 + 7.2 = 8.2

y-coordinate of M = -2 + (4/5)(5) = -2 + 4 = 2

wyzant

jon s.

mark m.

Raymond B.

5 0

1 year ago

Whats the answer then

Viktor [21]

Wheres the question??

3 0

3 years ago

Jill’s bowling scores are approximately normally distributed with mean 170 and standard deviation 20, while Jack’s scores are ap

miss Akunina [59]

Answer:

a) The probability of Jack scoring higher is 0.3446

b) They probability of them scoring above 350 is 0.2119

Step-by-step explanation:

Lets call X the random variable that determines Jill's bowling score and Y the random variable that determines jack's. We have

$X \simeq N(170,400)\\Y \simeq N(160,225)$

Note that we are considering the variance on the second entry, the square of the standard deviation.

If we have two independent Normal distributed random variables, then their sum is also normally distributed. If fact, we have this formulas:

$N(\lambda_1, \sigma^2_1) + N(\lambda_2, \sigma^2_2) = N(\lambda_1 + \lambda_2,\sigma^2_1 + \sigma^2_2) \\r* N(\lambda_1, \sigma^2_1) = N(r\lambda_1,r^2\sigma^2_1)$

for independent distributions $N(\lambda_1, \sigma^2_1)$ , $N(\lambda_2, \sigma^2_2)$ , and a real number r.

a) We define Z to be Y-X. We want to know the probability of Z being greater than 0. We have

$Z = Y-X = N(160,225) - N(170,400) = N(160,225) + (N(-170,(-1)^2 * 400) = N(-10,625)$

So Z is a normal random variable with mean equal to -10 and vriance equal to 625. The standard deviation of Z is √625 = 25.

Lets work with the standarization of Z, which we will call W. $W = (Z-\mu)/\sigma$ = (Z+10)/25. W has Normal distribution with mean 0 and standard deviation 1. We have

P(Z > 0) = P( (Z+10)/25 > (0+10)/25) = P(W > 0.4)

To calculate that, we will use the <em>known </em>values of the cummulative distribution function Φ of the standard normal distribution. For a real number k, P(W < k) = Φ(k). You can find those values in the Pdf I appended below.

Since Φ is a cummulative distribution function, we have P(W > 0.4) = 1- Φ(0.4)

That value of Φ(0.4) can be obtained by looking at the table, it is 0.6554. Therefore P(W > 0.4) = 1-0.6554 = 0.3446

As a result, The probability of Jack's score being higher is 0.3446. As you may expect, since Jack is expected to score less that Jill, the probability of him scoring higher is lesser than 0.5.

b) Now we define Z to be X+Y Since X and Y are independent Normal variables with mean 160 and 170 respectively, then Z has mean 330. And the variance of Z is equal to the sum of the variances of X and Y, that is, 625. Hence Z is Normally distributed with mean 330 and standard deviation rqual to 25 (the square root of 625).

We want to know the probability of Z being greater that 350, for that we standarized Z. We call W the standarization. W is s standard normal distributed random variable, and it is obtained from Z by removing its mean 330 and dividing by its standard deviation 25.

P(Z > 350) = P((Z - 330)/25 > (350-330)/25) = P(W > 0.8) = 1-Φ(0.8)

The last equality comes from the fact that Φ is a cummulative distribution function. The value of Φ(0.8) by looking at the table is 0.7881, therefore P(X+Y > 350) = 1 - Φ(0.8) = 0.2119.

As you may expect, this probability is pretty low because the mean value of the sum of their combined scores is quite below 350.

I hope this works for you!

Download pdf

6 0

3 years ago