All categories

3 years ago

What is the answer to 5a-2a+9

Mathematics

1 answer:

Artyom0805 [142]3 years ago

4 0

Your answer would be 3a + 9
Hope I helped!
~ Zoe

You might be interested in

Dylan is six years older than his sister. If his sister's age is represented by the variable s, which of the following expressio

FromTheMoon [43]

Answer:

HI! That would be s + 6. aka C. <3 have a good day/night

Step-by-step explanation:

5 0

3 years ago

Nate's classroom has three tables of different lengths. One has a length of 4 1/2 feet, another has a length of 4 feet, and a th

Anarel [89]

12 feet.
4 1/2= 4.5
4 1/2+ 4= 9.5 + 2.5 = 12

6 0

3 years ago

Read 2 more answers

A carton has a length of 2 1/4 feet, width of 1 3/5 feet, and height of 2 1/3 feet. What is the volume of the carton?

Alik [6]

Multiply 2 1/4, 1 3/5 and 2 1/3 together! It would be easier to turn these mixed fractions into improper fractions.

5 0

3 years ago

You invested $100 at 8.2% which is compounded annually for 7 years. How much will your $100 be worth in 7 years?

____ [38]

Answer:

57.4%

Step-by-step explanation:

8.2 × 7 = 57.4

hope this helps!!

7 0

2 years ago

Evaluate the function at the given numbers( correct to six decimal places). Use the results to guess the value of the limit or e

netineya [11]

Answer:

Value of the limit is 0.5.

Step-by-step explanation:

Given,

$F(x)=\frac{e^x-1-x}{x^2}$

When,

$x=1,F(1)=frac{e^1-1-1}{1}=e-2=0.718281$

$x=0.5, F(0.5)=\frac{e^0.5-1-0.5}{(0.5)^2}=0.594885$

$x=0.1, F(0.1)=\frac{e^0.1-1-0.1}{(0.1)^2}=0.517091$

$x=0.05, F(0.05)=\frac{e^0.05-1-0.05}{(0.05)^2}=0.508438$

$x=0.01, F(0.01)=\frac{e^0.01-1-0.01}{(0.01)^2}=0.501670 \hfill (1)$

Correct upto six decimal places.

Now,

$\lim_{x\to 0}F(x)=\lim_{x\to 0}\frac{e^x-1-x}{x^2}$ $(\frac{0}{0})$ form, applying L-Hospital rule that is differentiating numerator and denominator we get,

$\lim_{x\to 0}F(x)$

$=\lim_{x\to 0}\frac{e^x-1}{2x}$ $(\frac{0}{0})$ form.

$=\lim_{x\to 0}\frac{e^x}{2}=\frac{1}{2}=0.5\hfill (2)$

Limit exist and is 0.5. That is according to (1) we can see as the value of x lesser than 1 and tending to near 0, value of the function decreases respectively. And from (2) it shows ultimately it decreases and reach at 0.5, consider as limit point of F(x).

8 0

3 years ago