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3 years ago

35/100 and 5/100 are proportional right?

1 answer:

7 0

In order to know that, you need to divide it from other, if it would be perfect number then your answer will be "YES" & if they not then it will be "NO"

35/100 / 5/100

You can re-write it as:
35/100 * 100/5 = 35/5 = 7

So, they are proportional to each other,.

Hope this helps!

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3. What is the solution to the equation 3x = 15? Express the

ivanzaharov [21]

Answer:

x=2.4650

Step-by-step explanation:

I assume that you mean $3^x=15$

so let s use the ln() function

$ln(3^x)= xln(3)=ln(15)$

so x = ln(15)/ln(3)

x = 2.4650

4 0

3 years ago

What is the fractional value for pi?

irina1246 [14]

Pie equals 3.14 so if you turn that into a fraction you will get your answer

5 0

2 years ago

Read 2 more answers

Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel

Airida [17]

Answer:

89.1° or -1.4°

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

$(3) \, t =\dfrac{2}{\cos \theta}$

Substitute (3) into (2)

$-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}$

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

$-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )$

Set up a quadratic equation

$\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}$

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0

3 years ago

Would appreciate some help with this:<br><br> Verify (sinq+cosq)^2 - 1 = sin2q

Phantasy [73]

Hello from MrBillDoesMath!

Answer:

See Discussion below

Discussion:

(sinq + cosq)^2 = => (a +b)^2 = a^2 + 2ab + b^2

(sinq)^2 + (cosq)^2 + 2 sinq* cosq => as (sinx)^2 + (cosx)^2 = 1

1 + 2 sinq*cosq (*)

Setting a = b = q in the trig identity:

sin(a+b) = sina*cosb + cosa*sinb

sin(2q) = (**)

sinq*cosq + cosq*sinq => as both terms are identical

2 sinq*cosq

Combining (*) and (**)

(sinq + cosq)^2 = 1 + 2sinq*cosq => (**) 2sinq*cosq = sqin(2q)

= 1 + sin(2q)

Hence

(sinq + cosq)^2 = 1 + sin(2q) => subtracting 1 from both sides

(sinq + cosq)^2 - 1 = sin(2q)

The last statement is what we are trying to prove.

Thank you,

MrB

7 0

3 years ago

to find the product 3 3/8 * 4 1/9.tara rewrote 3 3/8 as 17/8 amd 4 1/9 as 13/9. she multiplies the fractions to find the product

Ymorist [56]

Answer:

The error Tara made is she rewrote incorrectly 3 3/8 as 17/8 and 4 1/9 as 13/9,

the corrected number can be rewrote as 3 3/8 as 27/8 and 4 1/9 as 37/9.

Step-by-step explanation:

To find the Product of:

$3\frac{3}{8}\times 4\frac{1}{9}$

The Number can be rewrote as,

$\frac{3\times8+3}{8}\times \frac{4\times9+1}{9}\\\\\frac{24+3}{8}\times \frac{36+1}{9}\\\\\frac{27}{8}\times \frac{37}{9}$

Tara made error here she rewrote the number incorrectly 3 3/8 as 17/8 amd 4 1/9 as 13/9.

Now multiplying the fraction we get

$\frac{999}{72}$

Because she rewrote incorrectly which led her answer to multiplication of fraction, the product too was incorrect which she wrote as 221/72.

3 0

3 years ago