Answer:
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Step-by-step explanation:
50%. students (in percent) who passed the second exam also passed the first exam.
Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.
Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.
Thus, both tests were passed by 40 of the 80 pupils who passed the second one:
40/80 = 1/2 = 50%.
Find out more on Percentage at:
brainly.com/question/24877689
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1.742 x 10^-3
<em>This is because you have to move the decimal so there is no non zero digits left in the decimal point and if the number of decimal places you move will be the exponent on the "10". If you move the decimal to the right it will be a negative and if you move it to the left it will be a positive.
</em>
The difference (faculty-student) in the sample proportions of those who believe that five minutes is not enough time for students to change classes typically varies about 0.096 from the true difference in proportions. Option D is correct.
<h3>What is the standard deviation?</h3>
It is a measurement of statistical data dispersion. The degree to which the value varies is known as standard deviation.
The standard deviation of the sampling distribution is found as;

The difference in the sample proportions of those who think five minutes is not enough time for students to switch classrooms generally differs by roughly 0.096 from the actual difference in proportions.
Hence option D is correct.
To learn more about the standard deviation, refer to: brainly.com/question/16555520.
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