The scale factor that was used to create triangle J’K’L’ is 1/3
<h3>How to determine the scale factor?</h3>
From the graph, we have the following highlights:
KL = 3
K'L' = 1
The scale factor (k) from JKL to J'K'L is calculated as:
Scale factor = K'L'/KL
This gives
k = 1/3
Hence, the scale factor that was used to create triangle J’K’L’ is 1/3
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Answer:
(-2,21)
Step-by-step explanation:
2 days ago, Paulo's commute time was halfway between his commute times 8 and 9 days ago.
8 days ago means that x-coordinate -8 represents this day. Count 8 units to the left and find that when x = -8, y = 24 minutes.
9 days ago means that x-coordinate -9 represents this day. Count 9 units to the left and find that when x = -9, y = 18 minutes.
Find halfway commute time between points (-8,24) and (-9,18):
then coordinates that Paulo should graph are
(-2, 21)
(-2 means 2 days ago, 21 is the halfway)
Answer:
91.8 ft
Step-by-step explanation:
So we can talk about the diagram, let's name a couple of points. The base of the tree is point T, and the top of the tree is point H. We want to find the length of TH given the length AB and the angles HAT and ABT.
The tangent function is useful here. By its definition, we know that ...
TA/BA = tan(∠ABT)
and
TH/TA = tan(∠HAT)
Then we can solve for TH by substituting for TA. From the first equation, ...
TA = BA·tan(∠ABT)
From the second equation, ...
TH = TA·tan(∠HAT) = (BA·tan(∠ABT))·tan(∠HAT)
Filling in the values, we get ...
TH = (24.8 ft)tan(87.3°)tan(9.9°) ≈ 91.8 ft
The height <em>h</em> of the tree is about 91.8 ft.
Answer:
3/1
Step-by-step explanation:
Answer:
Step-by-step explanation:
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