<span>We can, transform the raw scores to z-scores and use the standard normal curve to find the relative frequency of the scores.
I hope this helped!</span>
Answer:
2/3<9/10; I used 3/4 as a benchmark.
Step-by-step explanation:
2/3<1/2; I used 1/2 as a benchmark.
2/3 = 0.(20/3) = 0.667
1/2 = 0.(10/2) = 0.5
So this is wrong, as 0.667 > 0.5.
1/2=3/5; I used 1/4 as a benchmark.
1/2 = 0.(10/2) = 0.5
3/5 = 0.(30/5) = 0.6
0.5 != 0.6, so this is wrong.
2/3<9/10; I used 3/4 as a benchmark.
2/3 = 0.(20/3) = 0.667
9/10 = 0.(90/10) = 0.9
So this is correct, as 0.667 < 0.9
3/4<2/3; I used 1/2 as a benchmark.
3/4 = 0.(30/4) = 0.75
2/3 = 0.(20/3) = 0.667
0.75 > 0.667, so this is wrong.
Let x be the unknown number. The equation is going to be 7/28=25/x, now we cross multiply. 7*x=25*28, 7x=700, divide both sides by 7 and you should get 100, So, x=100 and 7/28=25/100
Answer
Is there any numbers or is it just like that?
Answer:
tell martha to buy huwei matebook x 2020 , its a good one
Step-by-step explanation:
