All categories

3 years ago

Complete the table. Please help!

Mathematics

1 answer:

pashok25 [27]3 years ago

4 0

Perimeter: 4, 8, 12, 16, 20
Area: 1, 4, 9, 16, 25

You might be interested in

John bought 6 dumplings for $3.00.

zubka84 [21]

Just make the slope as 1/2 remember rise over run and start at 0

3 0

4 years ago

Help I don't really get this!

Fantom [35]

Answer:

ask your teacher about this wag puro asasa sa iba Kaya ka pinag aaral para matutu ka right

Step-by-step explanation:

yes

6 0

3 years ago

Find the solution of this system of equations.

beks73 [17]

x= -8 + y
-9x + 6y= 9

substitute x= -8 + y into -9x + 6y= 9

-9x + 6y= 9
-9(-8 + y) + 6y= 9
72 - 9y + 6y = 9
-3y = -63
y = 21

x= -8 + y
x= -8 + 21
x = 13

solution (13, 21)

7 0

3 years ago

The number of square feet per house is normally distributed with a population standard deviation of 154 square feet and an unkno

11111nata11111 [884]

Answer: (1500.66,1599.34)

Step-by-step explanation:

Confidence interval for population mean:

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}$

,where $\overline{x}$ = Sample mean , n= Sample size, z* = critical two tailed z-value , $\sigma$ = population standard deviation.

As per given , we have

n= 16

$\sigma = 154$ square feet

$\overline{x}= 1550$ square feet

$\alpha= 1-0.80 = 0.20$

Critical z-value = $z_{\alpha/2}=z_{0.2/2}=z_{0.1}=1.2815$

Confidence interval for population mean:

$1550\pm (1.2815)\dfrac{154}{\sqrt{16}}\\\\ = 1550\pm (1.2815)\dfrac{154}{4}\\\\= 1550\pm 49.33775\\\\ =(1550-49.33775,\ 1550+49.33775)\\\\\approx (1500.66,\ 1599.34)$

Required confidence interval: (1500.66,1599.34)

6 0

3 years ago

I’m a little confused with this? Can someone walk me through this?

mina [271]

Answer:

A. 5.8

Step-by-step explanation:

From the given graph d has two coordinates;

the first coordinates of d = (0, 0)

the second coordinate of d = (-3 , -5), that is x = -3 when traced up and y = -5 when traced horizontal

The distance between the two coordinates = distance of d;

$distance \ between \ two \ coordinates = \sqrt{(x_2-x_1)^2 \ + \ (y_2-y_1)^2} \\\\d = \sqrt{(-3-0)^2 \ + \ (-5-0)^2}\\\\d = \sqrt{9 \ + \ 25} \\\\d = \sqrt{34} \\\\d = 5.83\\\\d = 5.8$

Option A is correct

6 0

3 years ago