A small kennel has budgeted to provide 10 gallons of water for its animals. Each cat receive one eight of a gallon per day and each dog receives one fourth of a gallon per day . Which inequality correctly represent the scenario.
a. 10 < -1/8c - 1/4d
b. 10 ≤ 1/8c + 1/4d
c 10 ≥ -1/8c - 1/4d
d. 10 ≥ 1/8c + 1/4d
Answer:
d. 10 ≥ 1/8c + 1/4d
Step-by-step explanation:
The kennel was budgeted to provide 10 gallons of water for its animals. The cat receives 1/8 of a gallon per day and each dog receive 1/4 of a gallon per day.
Since 10 gallons was budgeted for the animals the sum of the a gallon per day for the cat and dog will most likely not exceed 10 gallons. The animals will most likely consume less than the budgeted value or equals to the budgeted value.
note that the sum of 1/8 of a gallon for the cat and 1/4 of a gallon for the dog should be either less than 10 or equals to 10. This means 10 ≥ 1/8c + 1/4d .
They budgeted upto10 gallons of water, meaning that it CANNOT exceed 10. When turned around, you will see that everything is <em>less</em><em> </em><em>than</em><em> </em><em>or</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em>10.
If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds. The z-score for 173 pounds is given by: Referring to a standard normal distribution table, and using z = 0.66, we find: Therefore The answer is: 0.2546
