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KatRina [158]
4 years ago
15

The reaction of 0.779 g K with O2 forms 1.417 g potassium superoxide, a substance used in self-contained breathing devices. Dete

rmine the formula for potassium superoxide.
Chemistry
1 answer:
zhannawk [14.2K]4 years ago
3 0
First we need to find the number of moles of both K and O reacted
K - 0.779 g / 39 g/mol
  = 0.02 mol
the mass of O₂ reacted = 1.417 g - 0.779 g = 0.638 g
O₂ moles = 0.638 g / 32 g/mol
               = 0.02 mol 
the number of both K and O₂ moles reacted are equal 
therefore stoichiometry of K to O₂ reacted are 1:1 
then the formula of potassium superoxide is KO₂
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