C wave transfer energy, but not matter this because waves transfer energy from one place to the other without moving matter:) hope this helps!
Answer what there is no question
Answer:
Kinetic energy: ![6.024*10^{-20}](https://tex.z-dn.net/?f=6.024%2A10%5E%7B-20%7D)
Velocity: ![3.64*10^{5}](https://tex.z-dn.net/?f=3.64%2A10%5E%7B5%7D)
Explanation:
From the equations of the photo-electric effect,
We know:
![hv=hv_0+K.E](https://tex.z-dn.net/?f=hv%3Dhv_0%2BK.E)
Where,
1.
is the Planck's constant which is ![6.626*10^{-34}](https://tex.z-dn.net/?f=6.626%2A10%5E%7B-34%7D)
2.
are the frequency of light emitted and threshold frequencies respectively.
3.
is the kinetic energy of the electrons emitted.
By fact, we come to know that the threshold frequency of Zn is 300nm
And also
Where ,
1.
is the speed of light ![=3*10^8](https://tex.z-dn.net/?f=%3D3%2A10%5E8)
2.
is the wavelength.
Thus,
![\frac{hc}{d}=\frac{hc}{d_0}+K.E\\K.E=\frac{hc}{d}-\frac{hc}{d_0}\\K.E=hc*(\frac{1}{d}-\frac{1}{d_0})\\K.E=6.626*10^{-34}*3*10^8*(\frac{1}{275*10^{-9}}-\frac{1}{300*10^{-9}})\\K.E=6.024*10^{-20}kgm^2s^{-2}](https://tex.z-dn.net/?f=%5Cfrac%7Bhc%7D%7Bd%7D%3D%5Cfrac%7Bhc%7D%7Bd_0%7D%2BK.E%5C%5CK.E%3D%5Cfrac%7Bhc%7D%7Bd%7D-%5Cfrac%7Bhc%7D%7Bd_0%7D%5C%5CK.E%3Dhc%2A%28%5Cfrac%7B1%7D%7Bd%7D-%5Cfrac%7B1%7D%7Bd_0%7D%29%5C%5CK.E%3D6.626%2A10%5E%7B-34%7D%2A3%2A10%5E8%2A%28%5Cfrac%7B1%7D%7B275%2A10%5E%7B-9%7D%7D-%5Cfrac%7B1%7D%7B300%2A10%5E%7B-9%7D%7D%29%5C%5CK.E%3D6.024%2A10%5E%7B-20%7Dkgm%5E2s%5E%7B-2%7D)
Now to find velocity:
![K.E=\frac{1}{2}mv^2\\v^2=1.324*10^{11}\\v=3.64*10^5](https://tex.z-dn.net/?f=K.E%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%5C%5Cv%5E2%3D1.324%2A10%5E%7B11%7D%5C%5Cv%3D3.64%2A10%5E5)
Answer:
100 cg/1g
Step-by-step explanation:
1 cg = 0.01 g Multiply by 100
100 cg = 1 g
(a) is <em>wrong</em>. The correct conversion factor is 1000 cm³/1 L.
(b) is <em>wrong</em>. The correct conversion factor is 1000 mL/1 L.
(c) is <em>wrong</em>. The correct conversion factor is 1 m/10 dm.
The surroundings would lose heat.