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irga5000 [103]
3 years ago
14

WORTH 20 POINTS!! Need answer ASAP

Chemistry
1 answer:
sammy [17]3 years ago
8 0

Answer:

i cant see the image im good at chem if you can write it down in the comments ill answer it

Explanation:

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What is the answer to the question?​
Charra [1.4K]
The answer to your question is the number 3
8 0
3 years ago
Sound and light are both found as (4)
Mrrafil [7]

Answer:  

Waves; wavelength; electromagnetic energy; ultraviolet light.  

Explanation:  

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission.  

Sound travels faster through solids than it does through either liquids or gases.  

Lightwave can be defined as an electromagnetic wave that does not require a medium of propagation for it to travel through a vacuum of space where no particles exist.

Hence, sound and light are both found as waves, with a variety of wavelengths. The sun, a source of light waves specifically, releases a type of electromagnetic energy. It can be found as UVA or UVB types. These lights give off different levels of ultraviolet light, some of which can be harmful.

Additionally, the ultraviolet spectrum is divided into three categories and these are; UVA, UVB ,and UVC.

7 0
3 years ago
A bond where the electrons are shared equally is called a(an) ________ bond.
zubka84 [21]
Metallic bonds result when electrons are shared equally.

7 0
4 years ago
How many grams of barium sulfate can be produced from the reaction of 2.54 grams sodium sulfate and 2.54 g barium chloride? Na2S
Rama09 [41]

Answer: 2.796 grams

Explanation:

Na_2SO_4+BaCl_2\rightarrow 2NaCl+BaSO_4

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of sodium sulphate}=\frac{2.54g}{142g/mol}=0.018moles

\text{Number of moles of barium chloride}=\frac{2.54g}{208g/mol}=0.012moles

According to stoichiometry:

1 mole of BaCl_2 reacts with 1 mole of Na_2SO_4

0.012 moles of BaCl_2 will react with=\frac{1}{1}\times 0.012=0.012moles of Na_2SO_4

Thus BaCl_2 is the limiting reagent as it limits the formation of product. Na_2SO_4  is the excess reagent as (0.018-0.012)=0.006 moles are left unused.

1 mole of BaCl_2 produces 1 mole of BaSO_4

0.012 moles of BaCl_2 will produce=\frac{1}{1}\times 0.012=0.012moles of BaSO_4

Mass of BaSO_4=moles\times {\text {Molar mass}}=0.012\times 233=2.796g

Thus 2.796 grams of BaSO_4  are produced.

6 0
4 years ago
Please Answer the Question
KengaRu [80]

Answer:

Explanation:

I think it is D

6 0
3 years ago
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