The balanced equation for the reaction between NaOH and HCl is as follows NaOH + HCl ---> NaCl + H₂O stoichiometry of NaOH to HCl is 1:1 number of NaOH moles reacted - 0.1 mol/L x 0.054 L = 0.0054 mol number of HCl moles reacted = number of NaOH moles reacted since the molar ratio of acid to base is 1:1 therefore number of HCl moles reacted - 0.0054 mol the number of moles of HCl in 125 mL - 0.0054 mol therefore number of HCl moles in 1000 mL - 0.0054 mol / 125 mL x 1000 mL number of moles of solute in 1000 mL is known as the molarity concentration concentration of HCl is 0.0432 M
