Solve for ddd.
41 =12d-741=12d−741, equals, 12, d, minus, 7
d =d=d, equals
Hint #11 / 4
Let's add and then divide to get ddd by itself.
Hint #22 / 4
\begin{aligned} 41 &=12d-7 \\ \\ 41\blue{+7} &= 12d-7\blue{+7}~~~~~~\blue{\text{add }7} \text{ to each side}\\ \\ 41\blue{+7}&=12d-\cancel{ 7} {\blue{+}\cancel{\blue{7}}}\\ \\ 41\blue{+7}&=12d\end{aligned}
41
41+7
41+7
41+7
=12d−7
=12d−7+7 add 7 to each side
=12d−
7
+
7
=12d
Hint #33 / 4
\begin{aligned}48 &= 12d \\ \\ \dfrac{48}{\pink{12}} &= \dfrac{12d}{\pink{12}} ~~~~~~~\text{divide each side by } \pink{12} \text{ to get } d \text{ by itself }\\ \\ \dfrac{48}{\pink{12}}&=\dfrac{\cancel{12}d}{\cancel{\pink{12}}} \\ \\ \dfrac{48}{\pink{12}}&=d \end{aligned}
48
12
48
12
48
12
48
=12d
=
12
12d
divide each side by 12 to get d by itself
=
12
12
d
=d
Hint #44 / 4
The answer:
d=\green{4}~~~~~~~~d=4 d, equals, start color green, 4, end color green, space, space, space, space, space, space, space, space[Okay, got it!]
\begin{aligned} 41 &=12d-7 \\\\ 41 &\stackrel{?}{=} 12(\green{4})-7 \\\\ 41 &\stackrel{?}{=} 48-7 \\\\ 41 &= 41 ~~~~~~~~~~\text{Yes!} \end{aligned}
41
41
41
41
=12d−7
=
?
12(4)−7
=
?
48−7
=41 Yes!
Answer:
Step-by-step explanation:
9th square number = 81
5th square number=25
81-25=56
56 is a multiple of 8 as 8 x 7=56
The relation that is a function is relation (b)
<h3>How to determine the
relation that is a
function?</h3>
The ordered pairs in the option represent the given parameters
For a relation (i.e. the ordered pairs) to be a function, the following must be true:
Each y value on the ordered pair must have exactly one x value
i.e. no x value must point to the different y value
Having said that the relation that is a function is relation (b)
Hence, the the relation that is a function is relation (b)2
Read more about functions at
brainly.com/question/3381225
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Answer:
we conclude that the total number of perfect odd squares between 5 and 211 will be: 6
Step-by-step explanation:
Let us check by taking squares
As taking 14² = 256 would exceed 211, and 1² = 1 is smaller than 5.
Therefore, we conclude that the total number of perfect odd squares between 5 and 211 will be: 6