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Naddik [55]
3 years ago
13

Describe the first step you would use to solve the equation 2=7y+2-y

Mathematics
1 answer:
madreJ [45]3 years ago
8 0

Solve for ddd.

41 =12d-741=12d−741, equals, 12, d, minus, 7

d =d=d, equals  

Hint #11 / 4

Let's add and then divide to get ddd by itself.

Hint #22 / 4

\begin{aligned} 41 &=12d-7 \\ \\ 41\blue{+7} &= 12d-7\blue{+7}~~~~~~\blue{\text{add }7} \text{ to each side}\\ \\ 41\blue{+7}&=12d-\cancel{ 7} {\blue{+}\cancel{\blue{7}}}\\ \\ 41\blue{+7}&=12d\end{aligned}  

41

41+7

41+7

41+7

​    

=12d−7

=12d−7+7      add 7 to each side

=12d−  

7

​  +  

7

​  

=12d

​  

Hint #33 / 4

\begin{aligned}48 &= 12d \\ \\ \dfrac{48}{\pink{12}} &= \dfrac{12d}{\pink{12}} ~~~~~~~\text{divide each side by } \pink{12} \text{ to get } d \text{ by itself }\\ \\ \dfrac{48}{\pink{12}}&=\dfrac{\cancel{12}d}{\cancel{\pink{12}}} \\ \\ \dfrac{48}{\pink{12}}&=d \end{aligned}  

48

12

48

​  

12

48

​  

12

48

​  

​    

=12d

=  

12

12d

​         divide each side by 12 to get d by itself  

=  

12

 

12

d

​  

=d

​  

Hint #44 / 4

The answer:

d=\green{4}~~~~~~~~d=4        d, equals, start color green, 4, end color green, space, space, space, space, space, space, space, space[Okay, got it!]

\begin{aligned} 41 &=12d-7 \\\\ 41 &\stackrel{?}{=} 12(\green{4})-7 \\\\ 41 &\stackrel{?}{=} 48-7 \\\\ 41 &= 41 ~~~~~~~~~~\text{Yes!} \end{aligned}  

41

41

41

41

​    

=12d−7

=

?

12(4)−7

=

?

48−7

=41          Yes!

​

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But I can solve this anyway.


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Here that means we have two additional roots,


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Full set of roots:


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