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barxatty [35]
3 years ago
7

a worker earn $200 if she put $150 into a savings account what percent of her earnings did she put into a savings account

Mathematics
2 answers:
Allisa [31]3 years ago
6 0
He put 3/4 back into his savings.
solniwko [45]3 years ago
3 0
75% of her savings were added to her savings account
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Steven bought five bags of candies for $24.50 total. Which
vladimir2022 [97]

Answer:

4.9

Step-by-step explanation:

24.50 divided by 5 is 4.9

7 0
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Can you help meh answer for brianliest
Yakvenalex [24]

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1st One- 1 13/30

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3rd One- 1/6

Step-by-step explanation:

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Read 2 more answers
The function f(x) = 2x + 510 represents the number of calories burned when exercising, where x is the number of hours spent exer
riadik2000 [5.3K]

Answer: 789 calories burned while combining diet with 2 hours of exercise

Step-by-step explanation:

we have that

f(x)=2x+510

g(x)=200x-125

we know that

(f+g)(x)=f(x)+g(x)

substitute

(f+g)(x)=2x+510+200x-125

(f+g)(x)=202x+385

Find (f+g)(2)

For x=2 hours

substitute

(f+g)(2)=202(2)+385

(f+g)(2)=789\ calories

therefore

The answer is

789 calories burned while combining diet with 2 hours of exercise

8 0
3 years ago
[30 POINTS] Please help!!!
Len [333]

Answer:

Part 1) y=1.5x+5  

Part 2) y=-(2/3)x-(11/3)

Part 3) y=0.25x+2.75    

Part 4) y=-2x+5  

Part 5) y=0.5x-1  

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

m=3/2=1.5

point(-2,2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-2=1.5(x+2)

y=1.5x+3+2

y=1.5x+5

Part 2) we know that  

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

m1*m2=-1

the slope of the line 1 is equal to

m1=1.5

Find the slope m2

1.5*m2=-1

m2=-2/3

Find the equation of the line 2  

we have

m2=-2/3

point(-7,1)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-1=(-2/3)(x+7)

y=-(2/3)x-(14/3)+1

y=-(2/3)x-(11/3)

Part 3) we have

m=1/4=0.25

point(1,3)  

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-3=0.25(x-1)

y=0.25x-0.25+3

y=0.25x+2.75

Part 4) we have

m=-2

b=5 -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

y=mx+b

substitute the values

y=-2x+5

Part 5) we have that

The slope of the line 4 is equal to -2

so

the slope of the line perpendicular to the line 4 is equal to

-2*m=-1\\m=(1/2)=0.5

therefore

in this problem we have

m=0.5

point(-2,-2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y+2=0.5(x+2)

y=0.5x+1-2

y=0.5x-1

Part 6)

using a graphing tool

see the attached figure

3 0
3 years ago
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