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3 years ago

7

a worker earn $200 if she put $150 into a savings account what percent of her earnings did she put into a savings account

2 answers:

Allisa [31]3 years ago

6 0

He put 3/4 back into his savings.

solniwko [45]3 years ago

3 0

75% of her savings were added to her savings account

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Steven bought five bags of candies for $24.50 total. Which

vladimir2022 [97]

Answer:

4.9

Step-by-step explanation:

24.50 divided by 5 is 4.9

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3 years ago

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Yakvenalex [24]

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The function f(x) = 2x + 510 represents the number of calories burned when exercising, where x is the number of hours spent exer

riadik2000 [5.3K]

Answer: 789 calories burned while combining diet with 2 hours of exercise

Step-by-step explanation:

we have that

$f(x)=2x+510$

$g(x)=200x-125$

we know that

$(f+g)(x)=f(x)+g(x)$

substitute

$(f+g)(x)=2x+510+200x-125$

$(f+g)(x)=202x+385$

Find $(f+g)(2)$

For x=2 hours

substitute

$(f+g)(2)=202(2)+385$

$(f+g)(2)=789\ calories$

therefore

The answer is

789 calories burned while combining diet with 2 hours of exercise

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3 years ago

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

so

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

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3 years ago