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stepladder [879]
4 years ago
11

How do I solve inequalities as fractions?

Mathematics
2 answers:
andrey2020 [161]4 years ago
6 0
Then, choose another solution and evaluate the inequality for that value to make sure it is a true statement. Clear the fraction by multiplying both sides of the equation by 6. Add 4 to both sides to isolate the variable. Divide both sides by 2 to express the variable with a coefficient of 1.
Ghella [55]4 years ago
5 0
It's extactly the same except when you multiply something by a negative number the notation reverses
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60-10x = when x= 0 pls answer
satela [25.4K]

Answer:

Add '-10x' to each side of the equation.

60 + -10x = 10x + -10x

Combine like terms: 10x + -10x = 0

60 + -10x = 0

Add '-60' to each side of the equation.

60 + -60 + -10x = 0 + -60

Combine like terms: 60 + -60 = 0

0 + -10x = 0 + -60

-10x = 0 + -60

Combine like terms: 0 + -60 = -60

-10x = -60

Divide each side by '-10'.

x = 6

Simplifying

x = 6

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3 years ago
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artcher [175]
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2 years ago
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What is the volume of the soccer ball? Enter your answer in terms of π and round to the nearest cubic centimeter.
astraxan [27]

Answer:

380 CENTIMETERS

Step-by-step explanation:

PI R 2 THEN ROUND

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3 years ago
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Write an equation for the nth term of the arithmetic sequence
Zinaida [17]
The arithmetic sequence is increasing in 12 each time

18, 30, 42, 54, 66
12n 12, 24, 36, 48, 60

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8 0
3 years ago
Find the slope and the equation of the line tangent to f (x )equals StartFraction 2 x minus 1 Over x plus 7 EndFraction at x​ =
kondor19780726 [428]

Answer:

y=\frac{5}{27} x-\frac{1}{27}

Step-by-step explanation:

f(x)=\frac{2x-1}{x+7}

To find slope of f(x) at x=2, find the derivative f'(x)

apply quotient rule to find derivative

f(x)=\frac{2x-1}{x+7}\\f'(x)=\frac{2(x+7)-1(2x-1)}{(x+7)^2} \\f'(x)=\frac{15}{(x+7)^2}

f'(x) is the slope . Now find slope at x=2. plug in 2 for x

f'(x)=\frac{15}{(x+7)^2}\\f'(2)=\frac{15}{(2+7)^2}=\frac{5}{27}

find out f(x) when x=2

f(x)=\frac{2x-1}{x+7}\\f(2)=\frac{2(2)-1}{2+7}=\frac{1}{3}

Now frame the equation of the line

(2,1/3) slope = 5/27

y-y_1=m(x-x_1)\\y-\frac{1}{3}=\frac{5}{27} (x-2)\\y-\frac{1}{3}=\frac{5}{27} x-\frac{10}{27}\\\\y=\frac{5}{27} x-\frac{1}{27}\\\\

6 0
3 years ago
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