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stepladder [879]
3 years ago
11

How do I solve inequalities as fractions?

Mathematics
2 answers:
andrey2020 [161]3 years ago
6 0
Then, choose another solution and evaluate the inequality for that value to make sure it is a true statement. Clear the fraction by multiplying both sides of the equation by 6. Add 4 to both sides to isolate the variable. Divide both sides by 2 to express the variable with a coefficient of 1.
Ghella [55]3 years ago
5 0
It's extactly the same except when you multiply something by a negative number the notation reverses
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In September, a greeting card company's total profit was 22% less than it was in august. The total profit for the two months was
Trava [24]
Profit for August: x
Profit for September: x - 22%x
Total Profit for August & September: $689,000

x + x - 22% x = 689,000

2x - .22x = 689,000
1.78x = 689,000
x = 689,000/1.78
x = 387,078.65

August Profits: $387,078.65
September Profits: 387,078.65 - (22%)(387,078.65) = 387,078.65 - 85,157.30 = 301,921.35

August Profits: $387,078.65

September Profits
$301,921.35
5 0
3 years ago
Find the slope and y intercept of the line represented by each table
charle [14.2K]

Step-by-step explanation:


6 0
3 years ago
20=v+9-16 <br><br><br>20=v+9+ ( )<br><br><br>20=v-<br><br><br> =v
DIA [1.3K]

Answer:

v = 27

Step-by-step explanation:

20 = v + 9 - 16

20 = v + (9 - 16)

20 = v - 7

v = 27

4 0
2 years ago
7. The ratio of wins to losses for Loyola basketball was 4 to 1. If the team played 30 games, how
RoseWind [281]

Answer:

24:6

Step-by-step explanation:

It is 4 to 1. The ratios added up is 5. So 30 divided by 5 is 6. So 1 (the ratio) is 6 games. 4x6=24. So the new ratio is 24 to 6. 24 wins and 6 losses.

4 0
3 years ago
Find the surface area of the cylinder formed by the net. Use 3.14 for π.
sineoko [7]

Answer:

138.16 square feet

Step-by-step explanation:

The surface area of the cylinder consists of one rectangle and two circles.

1. The radius of the circle is 4 ft, then the area of the circle is

A_{circle}=\pi r^2 =\pi \cdot 4^2 =16\pi \ ft^2

2. The width of the rectangle is 1.5 ft, the length of the rectangle is the circumference of the circle.

Find the circumference:

C=2\pi r=2\pi \cdot 4=8\pi \ ft

Hence,

A_{rectangle}=1.5\cdot 8\pi =12\pi \ ft^2

3. The surface area of the cylinder is

SA=2A_{circle}+A_{rectangle}=\\ \\=2\cdot 16\pi +12\pi =32\pi +12\pi =44\pi \approx \\ \\\approx 44\cdot 3.14=138.16\ ft^2

8 0
3 years ago
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