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3 years ago

Find the equation of the line

Mathematics

2 answers:

kotegsom [21]3 years ago

7 0

Of the line of what?

Elina [12.6K]3 years ago

3 0

The equation is y = -3x + 5

Slope intercept form is y = mx + b, in this equation m = -3

-3(3) + 5 =
-9 + 5 =
-4
By plugging in the x coordinate it shows the line goes through (3, -4)

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Anyone know the answer

kykrilka [37]

You would need to change the slope to -6 because perpendicular lines have opposite reciprocal slopes.

5 0

3 years ago

What type of triangle is shown in the image?

kondaur [170]

Answer:

Acute Isosceles triangle.

7 0

3 years ago

Write a function number_of_pennies() that returns the total number of pennies given a number of dollars and (optionally) a numbe

seraphim [82]

Ok, first of all, it is important to understand that this function would depend on 2 variables; the number of dollars (x) and the number of pennies (y). Every dollar is equivalent to 100 pennies. So, if we are given x dollars, we have 100*x pennies. If we also have y pennies, we still get y pennies. We need to add these two to get the total amount of pennies. Thus, the correct function is:
f(x,y)=100*x+y

7 0

3 years ago

Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0

1 year ago

During a birthday party, 1/4 drank fanta orange, 1/3 took coca cola 1/5 of the remainder drank sprite and the rest took krest wh

Licemer1 [7]

Answer:

1/12

Step-by-step explanation:

Since 1/4 drank fanta orange and 1/3 took coca cola, the. remainder will be:

= 1 - (1/4 + 1/3)

= 1 - 7/12

= 5/12

Therefore, 1/5 of the remainder drank sprite, the fraction that drank sprite will be:

= 1/5 × 5/12

= 1/12

3 0

2 years ago