All categories

2 years ago

True or false: 3x^2+5x^3=8x^3

Mathematics

1 answer:

MrRa [10]2 years ago

7 0

Answer:

false

Step-by-step explanation:

You might be interested in

Enter an equation that gives the cost y of renting a car for x days from Rent-All.

Lelechka [254]

Answer:At the time of rental, an authorized hold will be secured on your credit/debit card provided to cover the estimated rental charges plus an additional $200.00 to cover additional charges that may be incurred.

Step-by-step explanation:

3 0

2 years ago

What is the solution to the equation-3(h+5)+2 = 4(h+6)- 9? h= 4 h= -2 h = 2 h = 4

ruslelena [56]

Expanding
-3h-15+2=4h+24-9
-3h-4h=24-9-2+15
-7h=28
h=4

8 0

2 years ago

What are two expressions that are equivalent to 6(5j + 2 + j)?

ziro4ka [17]

Answer:

1. 30j+12+6j

2. 36j+12

3. 6(6j+2)

Step-by-step explanation:

1. You just multiply so... 6x5j ... 6x2 ... 6xj

2. you multiply and then simplify so first you have 30j+12+6j, so you add like terms so... 30j+6j= 36j and then +12

3. you do what's in the parentheses first so 5j+j=6j so .... 6(6j+2)

5 0

3 years ago

Consider the points.

miskamm [114]

Answer:

6 units

Step-by-step explanation:

Use the distance formula, $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Plug the x and y values from the given points into the distance formula:

$\sqrt{([-4]-2)^{2}+(5-5)^{2}}$ .

Solve the square root:

$\sqrt{36}$ = $\sqrt{6^{2}}$ = $6$

3 0

2 years ago

If the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3

horrorfan [7]

Answer: The correct option is (B) 24 : 25.

Step-by-step explanation: Given that the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2 : 3.

We are to find the ratio of the area of R to the area of S.

Let 2x, 3x be the sides of rectangle R and y be the side of square S.

Then, according to the given information, we have

$\textup{Perimeter of rectangle R}=\textup{Perimeter of square S}\\\\\Rightarrow2(2x+3x)=2(y+y)\\\\\Rightarrow 5x=2y\\\\\Rightarrow \dfrac{x}{y}=\dfrac{2}{5}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Therefore, the ratio of the area of R to the area of S is

$\dfrac{2x\times3x}{y\times y}\\\\\\=\dfrac{5x^2}{y^2}\\\\\\=6\left(\dfrac{x}{y}\right)^2\\\\\\=6\times\left(\dfrac{2}{5}\right)^2~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\\=\dfrac{24}{25}\\\\=24:25.$

Thus, the required ratio of the area of R to the area of S is 24 : 25.

Option (B) is CORRECT.

6 0

3 years ago