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sukhopar [10]
3 years ago
15

Researchers found a linear relationship between tail-feather length (in mm) and weight (in g) in a random sample of 20 male long

-tailed finches raised in an aviary (with weights ranging from about 13 to 21g). Using software, we obtain the following output for predicting feather length when weight = 20g. What is a 95 % confidence interval for the mean weight of male long-tailed finches weighing 20g?
Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

   

Step-by-step explanation:

As far as I know, this question is not correct. I have the searched the internet and found a similar question which makes sense. In the correct question, 95% Confidence Interval is already given calculated from the software and

<em>95% prediction interval is asked (PI) for the weight of one male long tailed finch weighing 20 g.</em>

We have this data given in the correct question found on internet. And they have calculated this data using software:

New Obs = 20

Fit = 92.34

SE Fit = 5.26

95% Confidence Interval = (81.29, 103.38)

95% Prediction Interval = (67.61, 117.06)

Now, Just look at the prediction interval:

Now the formula for Prediction Interval = Point Estimate ± Margin of Error

Upper limit for prediction interval = 117.06

lower limit = 67.61

Formula for point estimate = (Upper + Lower)/2

Point Estimate = (117.06 + 67.61)/2

Point Estimate = 92.34

Formula for margin of error = (Upper - Lower)/2

Margin of Error = (117.06 - 67.61)/2

Margin of Error = 24.72

Formula for Prediction Interval = Point Estimate ± Margin of Error

PI = 92.34 ± 24.72

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Find the critical value necessary to form a confidence interval at the level of confidence shown below.
Rzqust [24]

Answer:

the critical value for 0.87 level of confidence is 1.51

Step-by-step explanation:

Given the data in the question;

level of confidence = 0.87

now,

1 - c = 0.87

c = 1 - 0.87

c = 0.13

c/2 = 0.13/2 = 0.065

now

1 - c/2  = 1 - 0.065 = 0.935

so our level of significance ∝ = 0.935

Now, the critical value will be;

Z_{0.935 is obtained as follows;

P( Z < z ) = 0.935

so we find the value from ( standard normal distribution table )

P( Z < 1.51 ) = 0.935

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\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: Acceleration_{dog} = 0

____________________________________

\large \tt Solution  \: :

A dog is moving at a constant speed of 8 m/s, that concludes that there's no change in its speed with respect to time.

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