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sukhopar [10]
3 years ago
15

Researchers found a linear relationship between tail-feather length (in mm) and weight (in g) in a random sample of 20 male long

-tailed finches raised in an aviary (with weights ranging from about 13 to 21g). Using software, we obtain the following output for predicting feather length when weight = 20g. What is a 95 % confidence interval for the mean weight of male long-tailed finches weighing 20g?
Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

   

Step-by-step explanation:

As far as I know, this question is not correct. I have the searched the internet and found a similar question which makes sense. In the correct question, 95% Confidence Interval is already given calculated from the software and

<em>95% prediction interval is asked (PI) for the weight of one male long tailed finch weighing 20 g.</em>

We have this data given in the correct question found on internet. And they have calculated this data using software:

New Obs = 20

Fit = 92.34

SE Fit = 5.26

95% Confidence Interval = (81.29, 103.38)

95% Prediction Interval = (67.61, 117.06)

Now, Just look at the prediction interval:

Now the formula for Prediction Interval = Point Estimate ± Margin of Error

Upper limit for prediction interval = 117.06

lower limit = 67.61

Formula for point estimate = (Upper + Lower)/2

Point Estimate = (117.06 + 67.61)/2

Point Estimate = 92.34

Formula for margin of error = (Upper - Lower)/2

Margin of Error = (117.06 - 67.61)/2

Margin of Error = 24.72

Formula for Prediction Interval = Point Estimate ± Margin of Error

PI = 92.34 ± 24.72

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Answer:

a

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = B(- 4, 2) and (x₂, y₂ ) = C(- 2, - 2)

m = \frac{-2-2}{-2+4} = \frac{-4}{2} = - 2

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 2, - 2), then

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3 years ago
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alexgriva [62]

x = # of hours the bike was rented.

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Subtract $12 from both sides.

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Divide both sides by $7

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En una sociedad participan 5 socios, colocando todos capitales iguales, lo unico que el primer socio estuvo 1 año y medio, el se
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Answer:

Socio 1 recibirá Q. 10,690, Socio 2 recibirá Q. 5,345, Socio 3 recibirá Q. 13,655, Socio 4 recibirá Q. 11,285 y Socio 5 recibirá Q. 14,255.

Step-by-step explanation:

Dado que en una sociedad participan 5 socios, colocando todos capitales iguales, lo único que el primer socio estuvo 1 año y medio, el segundo 9 meses, el tercero 5 meses mas que el primero, el cuarto 1 año 7 meses y el quinto 2 años, para determinar cuánto le toca a cada socio de una utilidad de Q. 55,230.00 se deben realizar los siguientes cálculos:

Socio 1 = 1.5 años

Socio 2 = 0.75 años

Socio 3 = 1.916 años

Socio 4 = 1.583 años

Socio 5 = 2 años

Total = 1.5 + 0.75 + 1.916 + 1.583 + 2 = 7.75

Socio 1 =

7.75 = 100

1.50 = X

1.50 x 100 / 7.75 = X

19.35 = X

55,230 x 0.1935 = 10,690

Socio 2 =

7.75 = 100

0.75 = X

0.75 x 100 / 7.75 = X

9.68 = X

55,230 x 0.0968 = 5,345

Socio 3 =

7.75 = 100

1.916 = X

1.916 x 100 / 7.75 = X

24.72 = X

55,230 x 0.2472 = 13,655

Socio 4 =

7.75 = 100

1.583 = X

1.583 x 100 / 7.75 = X

20.43 = X

55,230 x 0.2043 = 11,285

Socio 5 =

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2 = X

2 x 100 / 7.75 = X

25.81 = X

55,230 x 0.2581 = 14,255

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