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sukhopar [10]
3 years ago
15

Researchers found a linear relationship between tail-feather length (in mm) and weight (in g) in a random sample of 20 male long

-tailed finches raised in an aviary (with weights ranging from about 13 to 21g). Using software, we obtain the following output for predicting feather length when weight = 20g. What is a 95 % confidence interval for the mean weight of male long-tailed finches weighing 20g?
Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

   

Step-by-step explanation:

As far as I know, this question is not correct. I have the searched the internet and found a similar question which makes sense. In the correct question, 95% Confidence Interval is already given calculated from the software and

<em>95% prediction interval is asked (PI) for the weight of one male long tailed finch weighing 20 g.</em>

We have this data given in the correct question found on internet. And they have calculated this data using software:

New Obs = 20

Fit = 92.34

SE Fit = 5.26

95% Confidence Interval = (81.29, 103.38)

95% Prediction Interval = (67.61, 117.06)

Now, Just look at the prediction interval:

Now the formula for Prediction Interval = Point Estimate ± Margin of Error

Upper limit for prediction interval = 117.06

lower limit = 67.61

Formula for point estimate = (Upper + Lower)/2

Point Estimate = (117.06 + 67.61)/2

Point Estimate = 92.34

Formula for margin of error = (Upper - Lower)/2

Margin of Error = (117.06 - 67.61)/2

Margin of Error = 24.72

Formula for Prediction Interval = Point Estimate ± Margin of Error

PI = 92.34 ± 24.72

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love history [14]
If she runs half the distance to school, and runs the same back, this means that she suns 7/8 miles in a day. In 5 days, 5 x 7/8 = 35/8 miles (or 4.375 miles in 5 days).
8 0
3 years ago
Jean loves to go bird watching. One day, she saw 7 birds.The next day, she
Ludmilka [50]

Answer:

Jaw saw an average of 6 birds each day

Step-by-step explanation:

Given: One day, Jean saw 7 birds. The next day, she  saw 11 birds. The next day, she saw no birds.

To find: average number  of birds Jean saw each day

Solution:

Average is a central value of a set of terms.

Average of terms x_1,x_2,x_3,...,x_n is given by \frac{x_1+x_2+x_3+...+x_n}{n}

Number of birds, Jean saw on day one (x_1) = 7

Number of birds, Jean saw on the second one (x_2)  = 7

Number of birds, Jean saw on the third one (x_3) = 7

So,

average number  of birds Jean saw each day = \frac{x_1+x_2+x_3}{3} =\frac{7+11+0}{3}=\frac{18}{3}=6

Therefore,

Jaw saw an average of 6 birds each day

6 0
3 years ago
PLEASE HELP!<br><br> Reduce to simplest form.<br> 5/8 - (- 7/2)
Daniel [21]

Answer:

\huge\boxed{\sf 4\frac{1}{8} }

Step-by-step explanation:

\sf =\frac{5}{8} - (-\frac{7}{2} )\\\\Rule : ( - *- = +)\\\\\=\frac{5}{8} +\frac{7}{2} \\\\LCM = 8\\\\\=\frac{5+28}{8} \\\\\=\frac{33}{8} \\\\=4\frac{1}{8}

\sf =\frac{5}{8}+ \frac{7}{2}  \\\\=\frac{5+28}{8}

\sf =\frac{33}{8} \\\\=4\frac{1}{8}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
7 0
3 years ago
A candle maker has 4 1/2 pounds of clear wax. He wants to cut the wax into pieces that are 2/3 pound each. How many 2/3 pound pi
prisoha [69]

Answer:

a)  10  pieces of  2/3 pound  can be made.

b) 0.54 pounds of wax is left over.

Step-by-step explanation:

Total amount of clear wax available =  4\frac{1}{2}  = \frac{9}{2} pounds

So, the maker has in total 4.5 pounds of wax

Now, The weight of each piece = \frac{2}{3}  = 0.66  pounds

To find the number of pieces that can be made out of 4.5 pounds of wax,

let that number = n

So, n = \frac{\textrm{Total weight of the clear wax}}{\textrm{Weight of each wax}}

or, n = n = \frac{4.5}{0.66}  = 6.81

So, nearly 6 pieces can be made completely out of the clear wax

Left over amount of wax  = Total weight -  Weights of the pieces made

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                                            = 0.54 pounds

Hence, 0.54 pounds of wax is left over

8 0
3 years ago
The number line represents −4 1/2+3 1/4. What is the sum?
rjkz [21]

Answer:

C

Step-by-step explanation:

Rbrberbrb

5 0
2 years ago
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