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Ymorist [56]
3 years ago
10

Which measure is equivalent to 18,000 s?

Mathematics
2 answers:
abruzzese [7]3 years ago
6 0
The answer is 30 hours
Solnce55 [7]3 years ago
4 0

Answer:

30h

Step-by-step explanation:

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Julian wrote this number pattern on the board:
geniusboy [140]

Answer:


Step-by-step explanation:


10, 24 and 38 are composite numbers.


(10 can be divided by 5 and 2; 24 can be divided by 8, 3, 12 and 2; 38 can be divided by 19 and 2).


The others are prime numbers.

3 0
3 years ago
HELP PLEASE PLEASE!!!
AnnZ [28]

Answer:

im in online school

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Consider the following.3x + 3y = 8(a) Find y' by implicit differentiation.(b) Solve the equation explicitly for y and differenti
ludmilkaskok [199]

Answer:

a.y'=-1

b.y'=-1

c.Yes

Step-by-step explanation:

We are given that consider a function

3x+3y=8

Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable

Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.

a.3x+3y=8

Differentiate w.r.t x then we get

3+3\frac{dy}{dx}=0

3\frac{dy}{dx}=-3

\frac{dy}[dx}=\frac{-3}{3}=-1

\frac{dy}{dx}=y'=-1

b.3x+3y=8

3y=8-3x

y=\frac{8-3x}{3}

Differentiate w.r.t x then we get

\frac{dy}{dx}=\frac{-3}{3}=-1

\frac{dy}{dx}=y'=-1

When we substituting the value of y obtained from part b into a solution of part a then we get

y'=-1

Hence, solutions are consistent.

8 0
3 years ago
At what rate per annum ci will RS 2000 amount to RS 2315.35 in 3 years
Mashutka [201]

<u>ANSWER: </u>

Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%

<u>SOLUTION: </u>

Given,  

P = RS 2000

C.I = RS 2315.35

T = 3 years

We need to find the rate per annum. i.e. R = ?

We know that,  

When interest is compound Annually:

Amount $=\mathrm{P}\left(1+\frac{\mathrm{R}}{100}\right)^{n}$

Where p = principal amount

r = rate of interest

n = number of years

$2315.35=2000 \times\left(1+\frac{R}{100}\right)^{3}$

$\left(1+\frac{R}{100}\right)^{3}=\frac{2315.35}{2000}$

$\left(1+\frac{R}{100}\right)^{3}=1.157$

$1+\frac{R}{100}=\sqrt[3]{1.157}$

$1+\frac{R}{100}=1.0500$

$\frac{R}{100}=1.05-1$

$\frac{R}{100}=0.05$

R = 5%

Hence, rate per annum is 5 percent.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=785y%20%5Ctimes%20x%20%7C8%7C%20" id="TexFormula1" title="785y \times x |8| " alt="785y \times
steposvetlana [31]

The anwser is: 6280yx²

7 0
2 years ago
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