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Nina [5.8K]
3 years ago
5

(4a^3–11a^2)^2 pls hurry 10pts!!

Mathematics
1 answer:
podryga [215]3 years ago
4 0

Factor out the common term a^2

(a^2(4a - 11))^2

Use the Multiplication Distributive Property: (xy)^a = x^ay^a

(a^2)^2(4a - 11)^2

Use the Power Rule: (x^a)^b = x^ab

<u>a^4(4a - 11)^2</u>

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A theater has a seating capacity of 750 and charges $3 for children, s5 for students, and $7 for adults. At a certain screening
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Answer:

Between 150 and 450

Step-by-step explanation:

We are going to find the number by resolving  a system of linear equations.

First we write the system equations :

C+S+A=750

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The equation represents the ''full attendance''

The second equation :

3C+5S+7A=3450

This equation represents the totaled receipts.

The system :

C+S+A=750\\3C+5S+7A=3450

has the following associated matrix :

\left[\begin{array}{cccc}1&1&1&750\\3&5&7&3450\end{array}\right]

By performing elementary matrix operations we find that the matrix is equivalent to

\left[\begin{array}{cccc}1&0&-1&150\\0&1&2&600\\\end{array}\right]

The new system :

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Working with the equations :

C = 150 + A\\S = 600-2A

Our solution vector is :

\left[\begin{array}{c}C&S&A\end{array}\right] =\left[\begin{array}{c}150+A&600-2A&A\end{array}\right]

For example :

If 0 adults attended ⇒ A = 0

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A ≥ 0 ⇒ If A = 0 ⇒ C = 150

C = 150 is the minimum children attendance

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S = 600 -2A

S ≥0

600 - 2A ≥ 0

600 ≥ 2A

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A is restricted to the interval [ 0, 300]

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With C being an integer number (including 0)

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