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yarga [219]
3 years ago
15

Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to find a

right triangle with leg lengths of 16 and an odd number.
Mathematics
1 answer:
Levart [38]3 years ago
5 0
Hi,
2xy is even ==>2xy=16==>xy=8 ==>(x=8 and y=1) or (x=4 and y=2)
1) if x=4 and y=2 thenx²=16 and y²=4 x²+y²=16+4=20 is not oddx²-y² =16-4=12 is not also odd: impossible
2) if x=8 and y=1 thenx²=64, y²=1x²+y²=64+1= 65 possiblex²-y²=64-1=63The triple is (63,5,65) and 63²+5²=65²

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A taxi driver had 27 fares to and from the airport last Monday. The price for a ride to the airport is $14, and the price for a
OLga [1]

Answer:

(15, 12)

Step-by-step explanation:

Let's generate two systems of equations that fit this scenario.

Number of trips to the airport = x

Number of trips from the airport = y

Total number of trips to and from the airport = 27

Thus:

x + y = 27 => equation 1.

Total price for trips to the Airport = 14*x = 14x

Total price of trips from the airport = 7*y = 7y

Total collected for the day = $294

Thus:

14x + 7y = 294 => equation 2.

Multiply equation 1 by 7, and multiply equation 2 by 1 to make both equations equivalent.

7 × x + y = 27

1 × 14x + 7y = 294

Thus:

7x + 7y = 189 => equation 3

14x + 7y = 294 => equation 4

Subtract equation 4 from equation 3

-7x = -105

Divide both sides by -7

x = 15

Substitute x = 15 in equation 1

x + y = 27

15 + y = 27

Subtract both sides by 15

y = 27 - 15

y = 12

The ordered pair would be (15, 12)

7 0
3 years ago
Solve the value of Z 8 = 16
dezoksy [38]

Answer:

Z=2

Step-by-step explanation:

Z8=16

Z=16/8

Z=2

4 0
3 years ago
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liubo4ka [24]
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3 0
4 years ago
Read 2 more answers
Do number 5 pleaseee
swat32

Answer:

A

Step-by-step explanation:

16 × 2 = 32

20 × 2 = 40

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6 0
2 years ago
What are the solutions of x² + 6x - 6 = 10?
Likurg_2 [28]

Answer: x=- 8 or x=2


Step-by-step explanation:

1. To solve this problem you can applly the quadratic formula, which is shown below:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. The quadratic  equation is:

x^{2}+6x-6-10=0\\x^{2}+6x-16=0

3. Then:

a=1

b=6

c=-16

4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:

x=\frac{6+/-\sqrt{6^{2}-4(1)(-16)}}{2(1)}

x_1=-8\\x_2=2


4 0
3 years ago
Read 2 more answers
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