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yarga [219]
3 years ago
15

Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to find a

right triangle with leg lengths of 16 and an odd number.
Mathematics
1 answer:
Levart [38]3 years ago
5 0
Hi,
2xy is even ==>2xy=16==>xy=8 ==>(x=8 and y=1) or (x=4 and y=2)
1) if x=4 and y=2 thenx²=16 and y²=4 x²+y²=16+4=20 is not oddx²-y² =16-4=12 is not also odd: impossible
2) if x=8 and y=1 thenx²=64, y²=1x²+y²=64+1= 65 possiblex²-y²=64-1=63The triple is (63,5,65) and 63²+5²=65²

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What is 6x to the third power?
murzikaleks [220]

Answer:

216x

Step-by-step explanation:

  1. Write it out: 6x^{3}  
  2. 6^{3} = 216  
  3. Add in x: 216x

I hope this helps!

8 0
3 years ago
Read 2 more answers
A moving company charges $30 plus $0.15 Per mile to rent a moving van another company charges $15 plus $0.20 per mile to rent th
Ratling [72]
30 + x0.15=y is the first equation
15+x0.20=y is the second equation
Where in both x equals the amount of days it takes and y is your out come
You can solve this problem two ways one by finding the common denominator or just multiply x until you get the same awnser between the both of them
6 0
3 years ago
The population of a type of local dragonfly can be found using an infinite geometric series where a1 = 65 and the common ratio i
hram777 [196]
In mathematics, number sequencing of the same pattern are called progression. There are three types of progression: arithmetic, harmonic and geometric. The pattern in arithmetic is called common difference, while the pattern in geometric is called common ratio. Harmonic progression is just the reciprocal of the arithmetic sequence.

The common ratio is denoted as r. For values of r<1, the sum of the infinite series is equal to

S∞ = A₁/(1-r), where A1 is the first term of the sequence. Substituting A₁=65 and r=1/6:

S∞ = A₁/(1-r) = 65/(1-1/6)
S∞ = 78


6 0
3 years ago
If f x equals x -3 + g x equals 1 - x 2 - 9 find ( f og) (x and give any restrictions on its domain
evablogger [386]
\begin{gathered} f(x)=x-3 \\ g(x)=\frac{1}{x^2-9} \\ (\text{fog)(x)}=\frac{1}{x^2-9}-3 \end{gathered}

the denominator cannot be zero, because the division by zero is not defined, therefore:

\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}

Therefore the domain of (f o g)(x) is:

D\colon(-\infty,-3)\cup(-3,3)\cup(3,\infty)

3 0
1 year ago
Height: 15 ft <br> area: 285 square feet <br><br> find the missing dimension for the triangle
seraphim [82]
A=1/2 B×h
285=1/2×B×15
B=38 feet, so the base of the triangle is 38 feet. Hope it help!
4 0
3 years ago
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