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photoshop1234 [79]
4 years ago
10

Complete the factorization, x^2+5x+6=(x+ )(x+2)

Mathematics
2 answers:
Alborosie4 years ago
6 0

Answer:

x^{2} +5x +6= (x+3)(x+2)

Step-by-step explanation:

x^{2} +5x+6\\=x^{2} +2x+3x+6\\=x(x+2)+3(x+2)\\=(x+2)(x+3)

Masteriza [31]4 years ago
6 0

Answer:

Step-by-step explanation:

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The combined area of two squares is 45 square centimeter each side of one square is twice as long as the side of another square
Roman55 [17]

Let x be the side length of the small square. Then, the side length of the big square is 2x.

The respective areas are x^2 and (2x)^2=4x^2

So, the sum of the areas are x^2+4x^2=5x^2

We have

5x^2=45 \iff x^2=9 \iff x=\pm 3

We can't have negative lengts, so we choose x=3

So, the side length of the larger square is 6.

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Step-by-step explanation:

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4 years ago
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Witch of the following equations could be used to solve the problem? x2+2=36 2x+2=36 2x=36 2x+1=36
Tomtit [17]

Answer:

There is no problem stated, but here is the x's for every equations provided:

Step-by-step explanation:

a.) x²+2=36

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x=√34

b.) 2x + 2 =36

2x= 34

x= 17

c.)2x=36

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6 0
3 years ago
For each month of a given year except December, a worker earned the same monthly salary and donated one-tenth of that salary to
kiruha [24]

Answer:

D) 11/3

Step-by-step explanation:

Let x represent monthly salary.

We have been given that for each month of a given year except December, a worker earned the same monthly salary and donated one-tenth of that salary to charity.        

Salary earned in 11 months would be 11x.

Money donated in 11 months would be \frac{11x}{10}.

Further we are told that in December, the worker earned N times his usual monthly salary and donated one-fifth of his earnings to charity.

Salary for December would be Nx.

Money donated in December would be \frac{Nx}{5}.  

The worker's charitable contributions totaled one-eighth of his earnings for the entire year that is \frac{1}{8}\cdot (11x+Nx).

\frac{11x}{10}+\frac{Nx}{5}=\frac{1}{8}\cdot (11x+Nx)

Dividing whole equation by x, we will get:

\frac{11x}{10x}+\frac{Nx}{5x}=\frac{1}{8x}\cdot x(11+N)                

\frac{11}{10}+\frac{N}{5}=\frac{1}{8}\cdot (11+N)

\frac{11}{10}+\frac{N}{5}=\frac{11}{8}+\frac{N}{8}

Combine like terms:

\frac{N}{5}-\frac{N}{8}=\frac{11}{8}-\frac{11}{10}

\frac{N}{5}*40-\frac{N}{8}*40=\frac{11}{8}*40-\frac{11}{10}*40

8N-5N=11*5-11*4

3N=55-44

3N=11

\frac{3N}{3}=\frac{11}{3}\\\\N=\frac{11}{3}

Therefore, the value of N is 11/3 and option D is the correct choice.

4 0
3 years ago
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