To find the area of any regular (regular means all sides are = and all angles are =) poylgon when you know the length of the apothem and the length of the side you can use the formula:
A = (1/2)ap where a = the length of the apothem and p = the perimeter of the polygon. You can also use n*s in place of p where n = the number of sides of the polygon and s = the length of the side.
A= (1/2)(16)(19*8) (An octagon has 8 sides.)
A = 1216 in^2
Answer:
We do not have any problem to solve?
Step-by-step explanation:
Answer:
-2.61803398875, -0.38196601125
or
(-3±√5)/2
Step-by-step explanation:
First, expand. (2x+3)² = 4x²+12x+9=5
4x²+12x+4 = 0
Quadratic equations take the form ax²+bx+c = 0
In this case,
a = 4
b = 12
c = 4
You can solve with the equation x=(-b±√b²-4ac)/2a
Plug in:
(-12±√144-64)/8
(-12±√80)/8
(-12±√2^4×5)/8
(-12±4√5)/8
(-3±√5)/2
Final answer x = (-3±√5)/2
If you want decimal form: -2.61803398875, -0.38196601125
Answer:
1. right, 2. median, 3. range or the IQR
Step-by-step explanation:
