Apply the distributive property.<span>6⋅1+6<span>(−5m<span>)
</span></span></span>Multiply <span>66</span> by <span>11</span> to get <span>66</span>.<span><span>6+6<span>(−5m)</span></span><span>6+6<span>(-5m)</span></span></span>Multiply <span><span>−5</span><span>-5</span></span> by <span>66</span> to get <span><span>−30</span><span>-30</span></span>.<span><span>6−30m</span><span>6-30m</span></span>Reorder <span>66</span> and <span><span>−30m</span><span>-30m</span></span>.<span>−30m+<span>6
So your answer is </span></span>−30m+6
Answer:
The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.
Step-by-step explanation:
In this problem we have a normal ditribution with mean of 4.0 in and standard deviation of 1.5 in.
The proportion of the trees that are expected to have diameters greater than 5 inches is equal to the probability of having a tree greater than 5 inches.
We can calculate the z value for x=5 in and then look up in a standard normal distribution table the probability of z.
The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.
Step-by-step explanation:
use a formula method insert the variable
No they are not similar.
8/16 <> 12/12 or 8/12 <> 12/16
First work out the nth term then the 100th term:
the difference between the numbers is: 5
and that zero term is: -2
so the nth term is: 5n - 2
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now using the nth term we replace n with 100,
then we get: 498
the answer is the above in bold
hope it helped :)
