in this problem x equals 10
Step-by-step explanation:
jd
<span>(1 + 5 ) x 2 = 12 1
+ [(5 x 2) – 2] = 10 </span>
<span>1 + [5 x (2 – 2)] = 1 [1
+ (5 x 2)] – 2 = 9</span>
<span>8 = 12 – [8 / (4 / 2)] 11 = 12 – [(8 / 4) / 2]</span>
<span>½ = [(12 – 8 ) / 4] / 2 20
= 6 x 4 – 4 x 5 </span>ß----can’t figure it out …sorry
<span>0 = 6 x
(4 – 4) x 5 100
= [(6 x 4) – 4] x 5</span>
<span>24 = [14 –(8 -2)] x 3 0=
(14 –8) – (2 x 3)</span>
<span>12 = [{14 – 8)
- 2] x 3 12
= 14 – [8 - (2 x 3)]</span>
Answer:
see below
Step-by-step explanation:
<em><u>sin(a+b) = sin(a)cos(b) + cos(a)sin(b)</u></em>
sin(π+q) = sin(π)cos(q) + cos(π)sin(q)
sin(π) = 0
cos(π) = -1
therefore
sin(π+q) = 0*cos(q) -sin(q) = -sin(q)
