I need help please to find the answer

Mathematics

2 answers:

11Alexandr11 [23.1K]3 years ago

6 0

B. a like of symmetry is a strait line going form one place to another so if you drew a line from the top right corner to the bottom left corner you would get a triangle.

Katena32 [7]3 years ago

5 0

B! If you draw the line of symmetry diagonally, you have two triangles

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The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
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3 years ago

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The figure below shows the parcel of land on, which dallas, the zoo keeper , confines his zebras. His rule of thumb dictates tha

Irina18 [472]

Unfortunately, you haven't shared the "figure below" that shows the dimensions of this parcel of land. Without being able to calculate the area of the parcel, you cannot really answer this question exactly.

Suppose that the area of the parcel were 6000 square meters. Dividing that by 1500 square meters, we get 4, which represents the number of zebras that can live on this (example) parcel.

Figure out the area of your parcel, in square meters, and thend divide your result by 1500 square meters. This will give your your answer. Please note: your answer will be a COUNT of zebras. "meters" does not belong in this answer.

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4 years ago

Help please!! Step by step!!

GarryVolchara [31]

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