Answer:
Horizontal Asymptote: y=2
Vertical Asymptote: x=3
Step-by-step explanation:
One way: Look at graph
Look at for a horizontal or vertical line that both lines don't touch.
Second Way:
When you look for vertical asymptotes, you set the denominator equal to zero and solve.
For example, the second question has a denominator of x-3.
x-3=0
x=3 (This is the vertical asymptote)
When you look for horizontal asymptote, you do long division.
For example, the first question 
The answer will be 2. 2 is the quotient. You only want quotient not remainder.
y=2.
That would be 20 x 19 x 18 which equals 6840.
After first place is chosen, 19 spots left and so on.
The answer is 6840 ways.
Answer:
Step-by-step explanation:
If the mean is 110, and the standard devaition is 22,
1 standard dev. below the mean is 110-22
2 standard dev below the mean is 110-22-22
3 standard dev below the mean is 110-22-22-22
Hope that helps!
Alright so A is 6/10 * 5/9 = 1/3
B is 4/10 * 7/9 = 2/15
C is 6/10 * 4/9 = 4/15
I hope this helps
Using the graph, it is found that 976 passengers had carry-on luggage that weighed less than 20 lb.
<h3>Graph:</h3>
The graph is not given in this problem, but an internet search indicates that the information it contains is as follows:
- 120 passengers carry luggage of 4 lb or less.
- 222 passengers carry luggage between 5 lb and 9 lb.
- 378 passengers carry luggage between 10 lb and 14 lb.
- 256 passengers carry luggage between 15 lb and 19 lb.
- 90 passengers carry luggage between 20 lb and 24 lb.
- 40 passengers carry luggage between 25 lb or more.
Hence, the number of passengers with luggage below 20 lb is:
976 passengers had carry-on luggage that weighed less than 20 lb.
A similar problem, also involving the use of graph, is given at brainly.com/question/25836450
