Answer:
The approximate length of segment EF is 7 unit
Step-by-step explanation:
Given figure is the graph having E and F coordinate
The coordinate of point E = ( , ) = ( - 2 , -4 )
The coordinate of point F = ( , ) = ( 2 , 2 )
Let The distance between the points E and F = D
So, D =
or, D =
Or, D =
or, D =
∴ D =
I.e D = 7.21 unit
So, Approximate value of D = 7 unit
Hence The approximate length of segment EF is 7 unit . Answer
Answer:
9/7 or 1 2/7
Step-by-step explanation:
use the formula rise/run
Answer:
Point of intersections are (0, -7) and (5, -2).
Step-by-step explanation:
From the graph attached,
A straight line is intersecting the circle at the two points (0, 7) and (5, -2).
Now solve algebraically,
Equation of the line → y = x - 7 -------(1)
Equation of the circle → (x - 5)² + (y + 7)² = 25 -------(2)
By substituting the value of y from equation (1) to equation (2)
(x - 5)² + (x - 7 + 7)² = 25
(x - 5)² + x² = 25
x² - 10x + 25 + x² = 25
2x² - 10x = 0
x² - 5x = 0
x(x - 5) = 0
x = 0, 5
From equation (1),
y = 0 - 7 = -7
y = 5 - 7 = -2
Therefore, point of intersections are (0, -7) and (5, -2).
Answer:
385
Step-by-step explanation:
The standard deviation is the square root of the variance
so if the variance is 3.6, the standard deviation is the sqrt 3.6...
sqrt 3.6 = 1.897 <= if u need it rounded, it is 1.9 grams