Need help with 7,8,11,12 and the summary

The graph below shows the total cost for lunch, c, when Will and his friends buy a large salad to share and several slices of pi

Helga [31]

Answer:

2.50 dollars.

Step-by-step explanation:

Given:

Will and his friends buy a large salad to share and several slices of pizza, p.

The graph given shows the total cost for lunch, c and slices of pizza,p.

p is marked horizontally, and c vertically.

Observing the points marked we find that for every increase of one slice of pizza, the cost i.e. c on vertical line increases by 0.50 times vertical grid.

Since each grid equals 5 dollars vertically, we find 1/2 grid increase is equal to increase of 1/2(5 ) =2.50 dollars.

Thus for increase of one slice of pizza, 2.50 dollars cost is increased.

5 0

3 years ago

Read 2 more answers

A thermometer is taken from a room where the temperature is 25oc25oc to the outdoors, where the temperature is 0oc0oc. after one

Igoryamba

The thermometer will not directly indicate 0 °C because the thermometer need time to response. Especially alcohol in glass thermometers, the response time is slower than mercury in glass thermometers

3 0

3 years ago

to attend the football game it cost $8 for parking plus $59 per ticket if bryan paid $362 how many tickets did he purchase

PilotLPTM [1.2K]

Answer:

He bought 5.4 tickets or just 5 tickets

Step-by-step explanation:

You would add the parking fee and the football game for the total of $67. Then do 362 divided by 67

3 0

2 years ago

What is the simplified form of the equation fraction 4 over 5 n minus fraction 1 over 5 equals fraction 2 over 5 n

liubo4ka [24]

4/5n – 1/5 = 2/5n
Add 1/5 to both sides
4/5n = 2/5n + 1/5
Subtract 2/5n from both sides
2/5n = 1/5
Divide both sides by 2/5

n = 1/2

8 0

3 years ago

Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.

irina1246 [14]

Lagrange multipliers:

$L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)$

$L_x=y^2z^2+\lambda=0$
$L_y=2xyz^2+\lambda=0$
$L_z=2xy^2z+\lambda=0$
$L_\lambda=x+y+z-5=0$

$\lambda=-y^2z^2=-2xyz^2=-2xy^2z$

$-y^2z^2=-2xyz^2\implies y=2x$ (if $y,z\neq0$ )

$-y^2z^2=-2xy^2z\implies z=2x$ (if $y,z\neq0$ )

$-2xyz^2=-2xy^2z\implies z=y$ (if $x,y,z\neq0$ )

In the first octant, we assume $x,y,z>0$ , so we can ignore the caveats above. Now,

$x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2$

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of $f(1,2,2)=16$ .

We also need to check the boundary of the region, i.e. the intersection of $x+y+z=5$ with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force $f(x,y,z)=0$ , so the point we found is the only extremum.

4 0

3 years ago