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WITCHER [35]
2 years ago
7

Tom's coach keeps track of the number of plays that Tom carries the ball and how many yards he gains. Select all the statements

about independent and dependent variables that are true.
The dependent variable is the number of plays he carries the ball.
The independent variable is the number of plays he carries the ball.
The independent variable is the number of touchdowns he scores.
The dependent variable is the number of yards he gains.
The dependent variable is the number of touchdowns he scores.
Mathematics
1 answer:
Brums [2.3K]2 years ago
7 0

Answer:The dependent variable is the number of plays he carries the ball.

The independent variable is the number of touchdowns he scores.

The dependent variable is the number of yards he gains.

These are the ones that you need to choose.

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Help will mark brainlest
3241004551 [841]

Answer:

83

Step-by-step explanation:

82+87+83+77+70+80+88= 567

Then you divide that answer by the number of numbers you added by which is 7.

567/7= 81 so 83 was the missing number

6 0
3 years ago
I need help with this if someone could help me
Elodia [21]

Answer:

SSA (SIDE, ANGLE, SIDE)

Step-by-step explanation:

8 0
3 years ago
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The function f(x) = (10)–x is reflected across the x-axis to create the function g(x). Which ordered pair is on g(x)? (–2, 75) (
IRINA_888 [86]
Neither point is on either function.
f(x) reflected over the x-axis is
y=-10 + x
7 0
2 years ago
Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court
Ksju [112]

Answer:

(a)\dfrac{92}{117}

(b)\dfrac{8}{39}

(c)\dfrac{25}{117}

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
  • Two women are appointed

P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

5 0
2 years ago
Please write step by step of how you got the answer. Thankyou
stealth61 [152]

Answer:

The solution in the attached figure

Step-by-step explanation:

step 1

Place the numbers  -4, 4, 0, and -3 in the left side

Adds the numbers

-4+4+0-3=-3 ----> is correct

step 2

Place the numbers  3, -1, and -2 in the right side

Adds the numbers

-3+3-1-2=-3 ----> is correct

step 3

Place the numbers  1 and 2 in the base side

Adds the numbers

-4+1+2-2=-3 ----> is correct

The solution in the attached figure

7 0
3 years ago
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