Answer:
it can be solved using the formula hope it will hep you
Answer:
The approximated length of EF is 2.2 units ⇒ A
Step-by-step explanation:
<em>The tangent ratio in the right triangle is the ratio between the opposite side to the adjacent side of one of the acute angle in the triangle</em>
In the given figure
∵ The triangle DFE has a right angle F
∵ The opposite side to angle D is EF
∵ The adjacent side to angle D is DF
→ By using the tangent ratio above
∴ tan(∠D) = 
∵ DF = 6 units
∵ m∠D = 20°
→ Substitute then in the ratio above
∴ tan(20°) = 
→ Multiply both sides by 6
∴ 6 tan(20°) = EF
∴ 2.183821406 = EF
→ Approximate it to the nearest tenth
∴ 2.2 = EF
∴ The approximated length of EF is 2.2 units
Answer:
(1.6, 7.02)
Step-by-step explanation:
5 more brainliest for expert : )
Answer: The book costs $10 and the pen costs $4✔️
Step-by-step explanation:
Let B the cost of the book and let P the cost of the pen.
Then we know:
The book and the pen cost $14:
B + P = $14 } Equation 1
We also know:
The cost of the book is two dollars more than twice the cost of the pen.
B = 2P + $2 } Equation 2
Now we can substitute the value of B from the equation 2 in the equation 1:
2P + $2 + P = $14
3P = $14 - $2 = $12
P = $12/3 = $4 , cost of the pen
Since we know the value of B from the equation 2, we can calculate B:
B = 2P + $2 = 2x$4 + $2 = $8 + $2 = $10 , cost of the book
Answer: The book costs $10 and the pen costs $4✔️
<h3>Verify </h3>
We can substitute these values in equations 1 and 2 and check the results:
B + P = $14 } Equation 1
$10 + $4 = $14 ✔️check!
B = 2P + $2 } Equation 2
$10 = 2x$4 + $2 = $8 + $2 = $10 ✔️check!
<h2><em>Spymore</em></h2>
Answer:
A=3, B=4, C=-5
Step-by-step explanation:
So A represents the amplitude, which is the distance between the midline (C), the middle of the graph, and the maximum (or minimum). B is the distance of the period of the graph. In this case, we see that the midline is C=-5 because that is the halfway point of the sine function. We also see that the period distance is B=5-1=4, so our period would be 2π/4 or π/2. Our amplitude would be A=3 because |a|=|-5-(-2)|=|-5+2|=|-3|=3. Observe the graph to see this visually.