<span>A. cos(x) = cos(-x) [correct, since cos(x) is an even function]
B. Since the cosine function is even, reflection over the x-axis [y-axis] does not change the graph. [false]
C. cos(x) = -cos(x) [ false]
D. The cosine function is odd [even], so it is symmetrical across the origin. [false]</span>
Answer:
the answer is 28
Step-by-step explanation:
2×4+4+5
8+20
28
Answer:
121
Step-by-step explanation:
173-52
=121
Answer:
Class width = 9
Class limits = 20 - 28; 20 - 28; 29 - 37; 38 - 46; 47 - 55; 56 - 64; 65 - 73; 74 - 82.
Step-by-step explanation:
We are given;
Highest value = 82
Lowest value = 20
Frequency = 7
Formula for class width is;
Class width = (Highest Value - Lowest Value)/number of classes
Class width = (82 - 20)/7
Class width = 8.8 ≈ 9
Now,since class width is 9, limits between 20 and 82 would be done at intervals of 9.
Thus;
Class limits = 20 - 28; 20 - 28; 29 - 37; 38 - 46; 47 - 55; 56 - 64; 65 - 73; 74 - 82.
Step-by-step explanation:
Here, f(x) is the given polynomial.
By remainder Theorem,
When divided by (3x-1),
f(1/3) = -3........(1)
When divided by (x+1),
f(-1) = -7.........(2)
<em>Another</em><em> </em><em>polynomial</em><em> </em><em>is</em><em> </em><em>3</em><em>x</em><em>²</em><em>+</em><em>2</em><em>x</em><em>-</em><em>1</em>
Solving,
3x²+2x-1
= 3x²+3x-x-1
=3x(x+1)-(x+1)
=(3x-1)(x+1)
So
f(x) = (3x-1)(x+1)Qx + (ax+b)
For f(-1),
-7 = -a+b
b= a-7
For f(1/3),
-3 = a/3+b
or, -3 = a/3+a-7
or, 4×3 = 4a
or a = 3
Also, b = 3-7 =-4
Hence, remainder is (3x-4)
