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3 years ago

Please help me!!!!!!! It's very important!!!!

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

8 0

29,544.26 mm²

Area of a circle = (pi)(r²)
Area of a circle = (3.14)(97mm)²
Area of a circle = 29,544.26 mm²

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If a student randomly guesses at 20 multiple-choice questions, find the probability that the student gets exactly four correct.

ad-work [718]

Answer:

Probability = 0.190

Step-by-step explanation:

Given:

Number of questions, 'n' = 20

Each question has four choices.

Let event of choosing correct answer be success and its probability be represented by 'p'.

Therefore, event of choosing wrong answer is failure and its probability be represented by 'q'.

Now, probability of success is choosing one correct answer out of 4 options. So, $p=\frac{1}{4}=0.25$

Now, 'p' and 'q' are complements of each other. Therefore,

$q=1-p=1-0.25=0.75$

Now, we need 4 successes. Therefore, $x=4$

Using Bernoulli's theorem to find 'x' successes from 'n' questions, we get:

$P(x)=_{x}^{n}\textrm{C}p^xq^{n-x}$

Plug in 4 for 'x', 20 for 'n', 0.25 for 'p' and 0.75 for 'q'. Solve.

$P(4)=_{4}^{20}\textrm{C}(0.25)^4(0.75)^{20-4}\\P(4)=_{4}^{20}\textrm{C}(0.25)^4(0.75)^{16}\\P(4)=4845\times (0.25)^4\times (0.65)^{16}\\\\P(4)=0.1896\approx0.190$

Therefore, the probability of getting 4 correct answers out of 20 questions is 0.190.

6 0

2 years ago

Select the correct answer. Rachel traveled to five different areas (A, B, C, D, and E) to study the number of buckeye butterflie

nikitadnepr [17]

Answer:

Step-by-step explanation:

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2 years ago

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Use limits to find the area of the region bounded by the graph f(x)=4-2x^3 , the x-axis , and the vertical lines x=0 and x=1

gtnhenbr [62]

Answer:

$\frac{7}{2}$ square units.

Step-by-step explanation:

We have to use limits to find the area of the region bounded by the graph $f(x) = 4 - 2x^{3}$ , the x-axis, and the vertical lines x=0 and x=1.

So, the area will be

A = $\int\limits^1_0 {(4 - 2x^{3})} \, dx$

= $[4x - \frac{x^{4}}{2} ]^{1} _{0}$

= $4 - \frac{1}{2}$

= $\frac{7}{2}$ square units. (Answer)

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3 years ago

Jack crawled 3 ft and Christine crawled 3⁄4 the distance Jack crawled. If you add the distance they each crawled together, what

LUCKY_DIMON [66]

Christine crawled:
3 ft* (3/4)= 2.25 ft.

3 ft+ 2.25 ft= 5.25 ft

We already know that 1 ft= 12 in.

5.25 ft* (12in/ 1 ft)= 63 in.

The total distance the two children crawled together is 63 in~

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3 years ago

What is lcm 104 and 76

WITCHER [35]

Lcm of 104 and 76 = 1976

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3 years ago

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