Rewrite with only sin x and cos x. Sin2x-cos2x

1 answer:

4 0

$\bf \textit{Double Angle Identities}
\\\\
sin(2\theta)=2sin(\theta)cos(\theta)
\\\\
cos(2\theta)=
\begin{cases}
cos^2(\theta)-sin^2(\theta)\\
1-2sin^2(\theta)\\
2cos^2(\theta)-1
\end{cases}\\\\
-------------------------------\\\\
sin(2x)-cos(2x)\implies 2sin(x)cos(x)~~~~-~~~~2cos^2(x)-1
\\\\\\
\stackrel{common~factor}{2cos(x)}[sin(x)~~-~~cos(x)]-1$

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The play director spent 190190190 hours preparing for a play. That time included attending 353535 rehearsals that took varying a

dybincka [34]

Answer:

The equation $35x+93\frac{3}{4} =190$ gives average time spent on 35 rehearsals.

Step-by-step explanation:

We are supposed to find that what question does the equation $35x+93\frac{3}{4} =190$ finds answer of.

We can see that 35x represents time spent on 35 rehearsals and $93\frac{3}{4}$ is time spent on other responsibilities related to play. The sum of these times equals to total time spent on preparing the play.

Now let us solve our equation step by step.

$35x+\frac{375}{4} =190$

After subtracting $93\frac{3}{4}$ hours from 190 hours we will get time spent on 35 rehearsals.

$35x =190-\frac{375}{4}$

$35x =\frac{760-375}{4}$

$35x =\frac{385}{4}$

Time spent on 35 rehearsals is 96.25 hours and we are told that each rehearsal took different amount of time. Dividing 96.25 by 35 we will get average time spent on each rehearsal.

$x =\frac{96.25}{35}=2.75$