Question

I need help please and thank you (A AND B ARE NOT ANSWERS THEY ARE SEPARATE PROBLEMS)

Answer 1

Answer:

Part a) Wayne's savings before he spent $28 was $31.08

Part b) Stef's savings after she spent $28 was $9.29

Step-by-step explanation:

Part a)

Let

x ----> original amount of Wayne's savings

y ----> original amount of Stef's savings

we know that

Original ratio

$\frac{x}{y}=\frac{5}{6}$

$x=\frac{5}{6}y$ ----> equation A

After spending $28 each

$\frac{x-28}{y-28}=\frac{1}{4}$

Multiply in cross

$4x-112=y-25\\y=4x-112+25$

$y=4x-87$ ----> equation B

substitute equation A in equation B

$y=4(\frac{5}{6}y)-87$

solve for y

$\frac{20}{6}y-y=87$

$\frac{7}{3}y=87$

$y=37.29$

Find the value of x

$x=\frac{5}{6}(37.29)=31.08$

so

The original amount of Wayne's savings was $31.08 and the original amount of Stef's savings was $37.29

therefore

Wayne's savings before he spent $28 was $31.08

Part b) Find  Stef's savings after she spent $28

Subtract $28 from the original savings

so

$37.29-$28=$9.29

therefore

Stef's savings after she spent $28 was $9.29