For a parabola of the form

, its vertex is located at (h, k).
The vertex of f(x) is at (7, -1).
The vertex of g(x) is at (-6, -3).
To move (7, -1) to (-6, -3), we would have to go 13 units to the left and 2 units down. Therefore, moving f(x) 13 units left and 2 units down would map it onto g(x).
Rhombus (like a squished rectangle)
This is because there are always two pairs of parallel sides, equivalent pairs, and two angles that are acute, and two that are obtuse.
I hope this helps!
Answer:
hello,
answer C
Step-by-step explanation:
area of the rectangle=2b*b=2b²
area of the half cercle= 
Area in blue= 2b²-πc²/8
<span> y^2 = (3x + 1)^3 / 9x + 2
2*y*(dy/dx)=(9</span>(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ ((9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ (2*y*(9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(6x + 1))/ (2*y*(9x + 2)^2)
answer
A