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mario62 [17]
2 years ago
15

PLEASE ASAP!

Mathematics
2 answers:
slega [8]2 years ago
4 0

Answer: If I was doing this correctly from last year I think the answer would be b = 4

Step-by-step explanation:


Amanda [17]2 years ago
4 0

Answer:

might be  y= 4x + 16  

Step-by-step explanation:

i dont know if this is right but just check my answer.


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Can someone help me I’m struggling right now. <br><br> —<br> Just the table please
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TABLE / BOX

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I tried my best on putting it in order sorry if its not clear

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7 0
2 years ago
On a coordinate plane, points (1, 3), (5, 9), and (7, 12) are plotted. Which of the following statements are true about this gra
Natasha_Volkova [10]

Answer:

its 2,4,6 - b,d,f

Step-by-step explanation:

The three points form a straight line.

The graph does not pass through the origin.

The graph does not a show a proportional relationship.

4 0
3 years ago
Read 2 more answers
Factor the expression -15t-6
viktelen [127]
The only way the expression can be factored is if a -3 is pulled out...

-3(5t+2)
6 0
2 years ago
Use the table to write a quadratic function in vertex form. Then rewrite the function in standard form.
Kisachek [45]

Answer:

Step-by-step explanation:

The graph decreases at first, then changes direction at (2, 5).

y = a(x-2)^2 + 5

Plug in (1,11) and solve for a:

11 = a(1-2)^2 + 5

a = 6

Equation in vertex form:

y = 6(x-2)^2 + 5

8 0
2 years ago
Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court
Ksju [112]

Answer:

(a)\dfrac{92}{117}

(b)\dfrac{8}{39}

(c)\dfrac{25}{117}

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
  • Two women are appointed

P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

5 0
3 years ago
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